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scZoUnD [109]
3 years ago
12

Describe the difference between elements and compounds and atoms and molecules

Chemistry
1 answer:
dangina [55]3 years ago
3 0

Answer:

element are made up of the same type of atom, while a molecule is made up of 2 or more atoms of the same species. a compound is made up of 2 or more different types of atoms of different species

Explanation:

essentialy, elements and compounds are made both of atoms, except elements are made of one type of atom, while compounds are made up of 2 or more types of atoms.

an atom is the smallest building block of matter while molecules consist of one or more atoms bonded together

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The physical and chemical properties of a molecule depend on its structure. Here are two ball-and-stick models for two compounds
djyliett [7]

Answer:

Ethanol has covalent intramolecular bonds. Ethanol is polar. Ethanol has dispersion intermolecular forces. Dimethyl ether is polar. Dimethyl ether forms hydrogen bonds. Dimethyl ether has dispersion intermolecular forces.

Explanation:

Ethanol is not a carboxylic acid. It is an alcohol and it has covelent intramolecular bonds. It is polar and it also has dispersion intermolecular forces.

Dimethyl ether is also polar and it has forms hydrogen bonds. It also has dispersion intermolecular forces. Dimethyl ether does not have ionic intramolecular forces

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4 years ago
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How many moles are in 7.6 g of Ca
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Your answer would be 0.024951344877489 but rounding it would be 0.025 moles

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3 years ago
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sineoko [7]

Answer:

by freezing

Explanation:

8 0
3 years ago
For the following electron-transfer reaction:
creativ13 [48]

Answer:

1. The oxidation half-reaction is: Mn(s) ⇄ Mn²⁺(aq) + 2e⁻

2. The reduction half-reaction is: Ag⁺(aq) + 1e⁻ ⇄ Ag(s)  

Explanation:

Main reaction: 2Ag⁺(aq) + Mn(s) ⇄ 2Ag(s) + Mn²⁺(aq)

In the oxidation half reaction, the oxidation number increases:

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The reduction half reaction occurs where the element decrease the oxidation number, because it is gaining electrons.

Silver changes from Ag⁺ to Ag.

1. The oxidation half-reaction is: Mn(s) ⇄ Mn²⁺(aq) + 2e⁻

2. The reduction half-reaction is: Ag⁺(aq) + 1e⁻ ⇄ Ag(s)  

To balance the hole reaction, we need to multiply by 2, the second half reaction:

Mn(s) ⇄ Mn²⁺(aq) + 2e⁻

(Ag⁺(aq) + 1e⁻ ⇄ Ag(s)) . 2

2Ag⁺(aq) + 2e⁻ ⇄ 2Ag(s)  

Now we sum, and we can cancel the electrons:

2Ag⁺(aq) + Mn(s) + 2e⁻ ⇄ 2Ag(s) + Mn²⁺(aq) + 2e⁻

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mr_godi [17]
I am thinking Li & CI :)
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3 years ago
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