The mole fraction is calculated using the formula:
mole fraction of component A = # of moles of component A / # of total moles of the solution.
A) number of moles of ethanol
To calculate the number of moles of ethanol, you need its density, which will permit you to determine the mass of the 10.00 ml, and then convert into moles using the molar mass of ethanol.
The normal density of ethanol is 0.789 g/ml
density = mass / volume => mass = density * volume = 0.789 g/ml * 10.00 ml = 7.890 g
Molar mass of ethanol = 46.07 g/mol
number of moles = mass / molar mass = 7.890g / 46.07 g/mol = 0.1713 mol
B) number of moles of water
density of water = 1.00 g/mol
mass of water = density * volume = 1.00 g/mol * 2.00 ml = 2.00 g
number of moles of water = mass / molar mass = 2.00 g / 18.0 g/mol = 0.111 mol
C) mole fraction
mole fraction of ethanol = number of moles of ethanol / number of moles of solution
number of moles of ethanol = 0.1713 / (0.1713 + 0.111) = 0.1713 / 0.2824 = 0.607
Answer: 0.607
The volume of the final solution may be calculated by adding the volume of the two components. This is 10.00 ml of ethanol + 2.00 ml of water makes 12.00 ml of solution.
It is not clear what the second question is meant for. Some context is missing. If you know density and you know maqss (or can calculate the mass from other data) you do not need to measure the volume.
Answer:
As the amount of substances increases density will increase.
Explanation:
Density and mass have direct relation while density and volume has inverse relation. If the volume of substance is kept constant then the density of substance will increase with same factor as the mass of substance is increases.
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
Symbol:
The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.
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