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mr Goodwill [35]
3 years ago
5

Help fast please it's timed ​

Chemistry
2 answers:
lys-0071 [83]3 years ago
6 0

Answer: B its most likely

Iteru [2.4K]3 years ago
3 0

I think it would be d if I am wrong im am sorry

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what is the pressure, in atmospheres, of 2.97 mol h2 gas if it has a volume of 73 liters when the temperature is 298 k? 0.50 atm
Triss [41]
P x V = n x R x T

P x 73 = 2.97 x 0.082 x 298

P x 73 = 72.57492

P = 72.57492 / 73

P = 1.0 atm

hope this helps!




6 0
3 years ago
PLEASE HELP ASAP! BRAINLIEST WILL BE GIVEN PLEASE HELP!
inessss [21]

I think it is D I'm not positive

5 0
4 years ago
Read 2 more answers
WILL GIVE BRANLIEST!! EASY BUT I WAS TO LAZY TO LEARN!! WILL FOREVER BE GREATFUL!!! WILL GIVE BRANLIEST!! EASY BUT I WAS TO LAZY
maxonik [38]

Answer:

3. Which side of the chain should you count from when naming organic compounds?

C) Side that will give you the longest Carbon chain

4. What is the pH of a solution with a pOH of 10?

C) 4

pH + pOH = 14

pH + 10 = 14

pH = 14 - 10

pH = 4

<u>-TheUnknownScientist</u>

3 0
3 years ago
The new hybrid car can get 51.5 km/gal. It has a top speed of 40000.00 cm/min and is 4m long. How fast can the car go in m/hr?
horrorfan [7]

Answer:

The anawer of this question is 0.024 m/h

Explanation:

Other explanations of the question are additional.

4 0
3 years ago
Water is poured into a conical container at the rate of 10 cm3/sec. The cone points directly down, and it has a height of 20 cm
8090 [49]

Answer:

\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}

Explanation:

Hello,

The suitable differential equation for this case is:

\frac{dV}{dt}=10\frac{cm^3}{s}

As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:

\frac{dh}{dt} = ?*\frac{dV}{dt}

Of course, ?=\frac{dh}{dV}.

Now, since the volume of a cone is V=\pi r^2h/3 and the ratio r/h=15/20=3/4 or r=3/4h, the volume becomes:

V=\pi (\frac{3}{4} h)^2h/3= \frac{3}{16}\pi h^3

We proceed to its differentiation:

\frac{dV}{dh} =\frac{9}{16} \pi h^2\\\frac{dh}{dV} =\frac{16}{9 \pi h^2}

Then, we compute \frac{dh}{dt}

\frac{dh}{dt} = \frac{16}{9 \pi h^2}*\frac{dV}{dt}\\\frac{dh}{dt} = \frac{16}{9\pi h^2}*10\frac{cm^3}{s} =\frac{160}{9 \pi h^2}

Finally, at h=2:

\frac{dh}{dt}_{h=2cm} =\frac{160}{9\pi 2^2}\\\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{s}

Best regards.

4 0
4 years ago
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