I need help with Math

How do you determine the degree of a polynomial

yawa3891 [41]

Answer:

The degree of a polynomial refers to the highest degree of its individual terms having non-zero coefficients.

Step-by-step explanation:

The degree of a polynomial refers to the highest degree of its individual terms having non-zero coefficients. For example;

A quadratic polynomial is a polynomial of degree 2. This polynomial takes the general form;

$ax^{2}+bx+c$

where a, b, and c are constants. This is usually referred to as a quadratic polynomial in x since x is the variable. The highest power of x in the polynomial is 2, hence the degree of any quadratic polynomial is 2.

A second example, consider the cubic polynomial;

$ax^{3}+bx^{2}+cx+d$

The degree of this polynomial is 3.

6 0

3 years ago

Write slope intercept form of th equation of each line

Katen [24]

Answer:

y = 8/5x + (-4) or y = 8/5x -4

Step-by-step explanation:

Slope-intercept form is written like this:

y = mx + b

The variable m, represents slope and b, represents the y-intercept.

To find slope, you have to find the rise/run or in other words, change of y over change of x.

From the look of the line, the slope has to be positive because the line is going up.

To go from the bottom point to the top, we have to go up 8 points and go to the right 5 points. Thus the slope is 8/5.

Now for the y-intercept. This part is easy. Just ask yourself this...

"Which of the two points is on the y-axis?"

In this case, it is the bottom point which is -4.

So your equation should look like this:

y = 8/5x + (-4)

or y = 8/5x - 4 because when you have a plus sign and a minus sign, the result is negative.

hope this helps :)

5 0

2 years ago

Show with work please.

kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that $\text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$