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Ne4ueva [31]
3 years ago
8

Forensic psychiatrists and psychologists offer insight to investigators, attorneys, judges, and juries about a suspect's mental

state and their understanding of the crime committed O A True B. False​
Chemistry
1 answer:
slamgirl [31]3 years ago
5 0
The answer is A. True
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What is the density of an object with a mass of 1.663 g and a volume of 0.2009 mL
daser333 [38]
<span>8.278 g/mL The definition of density is mass per volume. So what you need to do is divide the known mass by the known volume. So 1.663 g / 0.2009 mL = 8.27775 g/mL But you also have to keep track of significant figures. Since both 1.663 and 0.2009 have 4 significant figures each, you need to round the result to 4 significant figures. So 8.27775 g/mL = 8.278 g/mL</span>
7 0
3 years ago
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Calculate the freezing point (in degrees C) of a solution made by dissolving 7.99 g of anthracene{C14H10} in 79 g of benzene. Th
mario62 [17]

<u>Answer:</u> The freezing point of solution is 2.6°C

<u>Explanation:</u>

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

where,

\Delta T_f = \text{Freezing point of pure solution}-\text{Freezing point of solution}

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_f = molal freezing point depression constant = 5.12 K/m  = 5.12 °C/m

m_{solute} = Given mass of solute (anthracene) = 7.99 g

M_{solute} = Molar mass of solute (anthracene) = 178.23  g/mol

W_{solvent} = Mass of solvent (benzene) = 79 g

Putting values in above equation, we get:

5.5-\text{Freezing point of solution}=1\times 5.12^oC/m\times \frac{7.99\times 1000}{178.23g/mol\times 79}\\\\\text{Freezing point of solution}=2.6^oC

Hence, the freezing point of solution is 2.6°C

8 0
3 years ago
2) A box experiences a force of 2 N to the left and 3 N to the right. Which is true of the box's motion? A) The box will slow do
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D, as forces are unbalanced
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If nitrogen and hydrogen combine in a combustion reaction, what would the product of the reaction be?
kow [346]

Co2

Explanation:

CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H2O (l)

4 0
3 years ago
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Naming compounding<br> N2O
solniwko [45]

Answer:

Nitrogenous oxide/ nitrogen oxide

Explanation:

N2O is nitrogen oxide

6 0
2 years ago
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