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motikmotik
3 years ago
9

Which of the following is true of ionic bonds?

Chemistry
1 answer:
emmasim [6.3K]3 years ago
5 0

Answer:

D: The bond is created by oppositely charged metal and nonmetal atoms.

Explanation:

An ionic metal basically involves a metal and a nonmetal in bonding. A metal is a cation with a + charge and a nonmetal is a anion with a - charge. I will give you an example. Magnesium Chloride is a ionic bond. This is because Magnesium is a metal with a +2 charge(so it is a cation). Chloride or Chlorine is a nonmetal because it has a -1 charge.(so it is a anion). The chemical formula for magnesium chloride is MgCl2.

Hope my answer helped! Have a great day.

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A helium-filled weather balloon has a volume of 512 L at 18.9°C and 756 mmHg. It is released and rises to an altitude of 2.14 km
vazorg [7]

633.97 L

Explanation:

Well use the combined gas law;

P₁V₁T₁ = P₂V₂T₂

We need to change the temperatures into Kelvin;

18.9°C= 292.05 K

5.9°C = 279.05 K

756 * 512 * 292.05 = 639 * V₂ * 279.05

113,044,377.6 = 178,312.95 V₂

V₂ = 113,044,377.6 / 178,312.95

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3 0
3 years ago
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Phosphorus trichloride gas and chlorine gas react to form phosphorus pentachloride gas: PCl3(g)+Cl2(g)⇌PCl5(g). A 7.5-L gas vess
Tpy6a [65]

Answer:

The equilibrium constant in terms of concentration that is, K_c=3.6243\times 10^{3} .

Explanation:

PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

The relation of K_c\& K_p is given by:

K_p=K_c(RT)^{\Delta n_g}

K_p= Equilibrium constant in terms of partial pressure.=98.1

K_c= Equilibrium constant in terms of concentration  =?

T = temperature at which the equilibrium reaction is taking place.

R = universal gas constant

\Delta n_g = Difference between gaseous moles on product side and reactant side=n_{g,p}-n_{g.r}=1-2=-1

98.1=K_c(RT)^{-1}

98.1 =\frac{K_c}{RT}

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The equilibrium constant in terms of concentration that is, K_c=3.6243\times 10^{3} .

5 0
3 years ago
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RoseWind [281]

The trajectory of their motion knocked the Earth into a different orbit.

3 0
4 years ago
How much time will it take a car traveling at an average of 75 mph to go a distance of 225 miles​
mojhsa [17]

Time taken = 3 hours

<h3>Further explanation</h3>

Given

speed : 75 mph

distance : 225 miles

Required

time taken

Solution

An equation of constant velocity motion  

\large {\boxed {\bold {d = v \times \: t}}}

d = distance = m  

v = speed = m / s  

t = time = seconds  

Input the value :

t = d : v

t = 225 miles : 75 miles/hour

t = 3 hours

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