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2 years ago

Which of the following is true of ionic bonds?

Chemistry

1 answer:

emmasim [6.3K]2 years ago

5 0

Answer:

D: The bond is created by oppositely charged metal and nonmetal atoms.

Explanation:

An ionic metal basically involves a metal and a nonmetal in bonding. A metal is a cation with a + charge and a nonmetal is a anion with a - charge. I will give you an example. Magnesium Chloride is a ionic bond. This is because Magnesium is a metal with a +2 charge(so it is a cation). Chloride or Chlorine is a nonmetal because it has a -1 charge.(so it is a anion). The chemical formula for magnesium chloride is MgCl2.

Hope my answer helped! Have a great day.

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2. Sitting on a bench top are several samples: lithium metal (d = 0.53 g/mL), gold (d = 19.3 g/mL), aluminum (d = 2.70 g/mL), an

Snezhnost [94]

Answer:

The sample of lithium occupies the largest volume.

Explanation:

Given the densities for the four elements, we have the expression $d=\frac{m}{V}$ that shows the relationship between mass and Volume to express the density of an element.

For each element we have:

$d_{lithium}=\frac{m_{lithium}}{V_{lithium}}=0.53g/mL$

$d_{gold}=\frac{m_{gold}}{V_{gold}}=19.3g/mL$

$d_{aluminum}=\frac{m_{aluminum}}{V_{aluminum}}=2.70g/mL$

$d_{lead}=\frac{m_{lead}}{V_{lead}}=11.3g/mL$

The problem says that all the samples have the same mass, so:

$m_{lithium}=m_{gold}=m_{aluminum}=m_{lead}=m$

it means that m is a constant

Now, solving for the Volume in each element and with m as a constant, we have:

$V_{lithium}=\frac{m}{d_{lithium}}$

$V_{lithium}=\frac{1}{0.53\frac{g}{mL}} *m$

$V_{lithium}=1.88\frac{mL}{g}*m$

$V_{gold}=\frac{m}{d_{gold}}$

$V_{gold}=\frac{1}{19.3\frac{g}{mL}} *m$

$V_{gold}=5.18*10^{-2}\frac{mL}{g}*m$

$V_{aluminum}=\frac{m}{d_{aluminum}}$

$V_{aluminum}=\frac{1}{2.70\frac{g}{mL}} *m$

$V_{aluminum}=3.70*10^{-1}\frac{mL}{g}*m$

$V_{lead}=\frac{m}{d_{lead}}$

$V_{lead}=\frac{1}{11.3\frac{g}{mL}} *m$

$V_{lead}=8.85*10^{-2}\frac{mL}{g}*m$

If we assume m = 1g, we find that:

$V_{lithium}=1.88mL$

$V_{gold}=5.18*10^{-2}mL$

$V_{aluminum}=3.70*10^{-1}mL$

$V_{lead}=8.85*10^{-2}mL$

So we can see that the sample of lithium occupies the largest volume with 1.88mL

Note that m only can take positive values, so if you change the value of m, always will be the lithium which occupies the largest volume.

4 0

2 years ago

How many mg is 59.0 kg in scientific<br> notation?

mina [271]

It would be 59000000 milligrams

8 0

2 years ago

You push your friend up the street with a force of 200N. How much work did you do if you traveled 15m?

VARVARA [1.3K]

Answer:

3000J

Explanation:

Formula: Work = Force × Distance

Solution: Work = 200N × 15m

Answer = 3000N/m or 3000J

4 0

1 year ago

Ammonium perchlorate NH4ClO4 is the solid rocket fuel used by the U.S. Space Shuttle. It reacts with itself to produce nitrogen

svet-max [94.6K]

Answer: 0.99 grams of chlorine gas is produced by the reaction of 3.3g of ammonium perchlorate

Explanation:

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$\text{Number of moles of } NH_4ClO_4=\frac{3.3g}{117.5g/mol}=0.028moles$

The decomposition of ammonium perchlorate is :

$2NH_4ClO_4\rightarrow Cl_2+N_2+2O_2+4H_2O$

According to stoichiometry :

2 moles of $NH_4ClO_4$ produce = 1 mole of $Cl_2$

Thus 0.028 moles of $NH_4ClO_4$ produce= $\frac{1}{2}\times 0.028=0.014moles$ of $Cl_2$

Mass of $Cl_2=moles\times {\text {Molar mass}}=0.014moles\times 71g/mol=0.99g$

Thus 0.99 grams of chlorine gas is produced by the reaction of 3.3g of ammonium perchlorate

5 0

2 years ago

What is the molarity of a solution that contains 9.63 grams of HCI in 1.5 liters of solution

vovikov84 [41]

Molar mass HCl = 1.01 + 35.45 => 36.46 g/mol

number of moles:

mass HCl / molar mass

9.63 / 36.46 => 0.2641 moles of HCl

Therefore:

M = moles / Volume ( in liters )

M = 0.2641 / 1.5

M = 0.1760 mol/L⁻¹

6 0

2 years ago