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3 years ago

PLEASE ANSWER...........WILL MARK BRAINLIEST!!!!!!!

Chemistry

1 answer:

ANTONII [103]3 years ago

3 0

Answer:

<h2>The Alkali metal halide may precipitate or there may be no change at all</h2>

Explanation:

Alkali metal cations are positively charged. Halogen anions are negatively charged. When a solution of Alkali metal cations is added to a solution of Halogen anions, there are two possibilities :

The alkali metal halide( salt formed from reation of the two ions) may precipitate if the Ionic product is higher than the Solubility product.
However, if it can remain in the solution, it will remain so. No chemical changes happen with respect to these both ions. Nothing willl happen.

There is no reaction happening in either of the cases because both species are already in ionic form before addition, hence they continue to be in this form.

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3 years ago

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Answer:

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3 years ago

What is the molarity of a solution containing 17.0 g of KCl in 213 mL of KCl solution?

Anarel [89]

Answer:

1.070MKCl

Explanation:

So we know that the original formula is M= n/L (n being moles of solute, L being liters of solvent)

Since we do not have liters in this problem, we would need to convert milliliters to liters

213 mL= 0.213 L

We then see that we do not have moles, but we do have a mass, being 17.0 g. we would need to convert these grams to moles, giving us 0.228 mol.

Then, you would plug in 0.228 for your n, and now you are ready to solve your original formula, plugging everything in.

M=n/L

M=0.228 mol/0.213L

M= 1.070MKCl

I know this was long, but I hope this helps (:

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3 years ago