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3 years ago

How many atoms are in 5Cao4?

Chemistry

1 answer:

vladimir1956 [14]3 years ago

5 0

Answer:

There are 30 atoms in total

Explanation:

There is 5 carbon, 5 of whatever A is and 4 oxygens but since the whole symbol has been multiplied by 5 there would be 20 oxygen

So 20 + 5 + 5 = 30 atoms

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Write the number 345 in scientific notation, with the same number of significant figures:

uranmaximum [27]

Answer:

3.45 x 10^2

Explanation:

345= 3 SF

3.45 x 10^2= 3 SF

8 0

3 years ago

Geologists have a rule of thumb: when molten rock cools and solidifies, crystals of compounds with the smallest lattice energies

lutik1710 [3]

Geologists have a rule of thumb: when molten rock cools and solidifies, crystals of compounds with the smallest lattice energies appear at the bottom of the mass because of high power of solubility.

<h3>What is lattice energy? </h3>

The lattice energy is defined as the energy change upon the formation of one mole of crystalline ionic compound from its same constituent ions, that are assumed to be initially in the state of gases. It is also defined as measure of the cohesive forces which bind ionic solids together.

As the lattice energy of the ionic compound increase the solubility of that particular compound decrease. Hence compound which have low lattice energy are more soluble than compound having high lattice energy. When molten rocks cools and solidified, the compound having smallest lattice energy become more soluble than crystals of compound which have large lattice energy. Therefore, crystal of compound with the smallest lattice energy start appearing at the bottom of the mass.

Thus, we concluded that due to high solubility power of compound with low lattice energy appear at the bottom of the mass.

learn more about lattice energy:

brainly.com/question/13169815

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4 0

1 year ago

Why flame tests are not useful for all elements?

Shalnov [3]

Not all elements have strong visible spectra in a flame

3 0

3 years ago

Read 2 more answers

Round 0.007062 to 4 significant numbers

mafiozo [28]

Answer

its already rounded

Explanation:

8 0

3 years ago

Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e

notsponge [240]

Answer: The concentration of $Sn^{2+}$ in the cell is $9.0\times 10^{-3}M$

Explanation:

We are given:

Oxidation half reaction: $Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-$ $E^o_{Zn^{2+}/Zn}=-0.76V$

Reduction half reaction: $Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)$ $E^o_{Sn^{2+}/Sn}=-0.136V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.