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Makovka662 [10]
3 years ago
5

What happens when the compound MgO is formed?

Chemistry
2 answers:
OleMash [197]3 years ago
5 0

I would say that the first answer choice makes sense since the charge of Oxygen is +2. But I may be wrong, try it out!

ludmilkaskok [199]3 years ago
5 0

Answer: Oxygen receives two electrons from magnesium.

Explanation:

An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element and the element which accepts the electrons is known as electronegative element. This bond is formed between a metal and an non-metal.

Electronic configuration of magnesium:

[Mg]=1s^22s^22p^63s^2

Magnesium atom will loose two electrons to gain noble gas configuration and form magnesium cation with +2 charge.

Mg^{2+}]=1s^22s^22p^63s^0

Electronic configuration of oxygen:

[O]=1s^22s^22p^4

Oxygen atom will gain two electrons to gain noble gas configuration and form oxide ion with -2 charge.

[O^{2-}]=1s^22s^22p^6

Thus Mg^{2+} and O^{2-} combine to form MgO.

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an engineer wishes to design a container that will hold 12.0 mol of ethane at a pressure no greater than 5.00x10*2 kPa and a tem
OleMash [197]

Answer:

The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.

Explanation:

Assume that ethane behaves as an ideal gas under these conditions.

By the ideal gas law,

P\cdot V = n\cdot R\cdot T,

\displaystyle V = \frac{n\cdot R\cdot T}{P}.

where

  • P is the pressure of the gas,
  • V is the volume of the gas,
  • n is the number of moles of particles in this gas,
  • R is the ideal gas constant, and
  • T is the absolute temperature of the gas (in degrees Kelvins.)

The numerical value of R will be 8.314 if P, V, and T are in SI units. Convert these values to SI units:

  • P =\rm 5.00\times 10^{2}\;kPa = 5.00\times 10^{2}\times 10^{3}\; Pa = 5.00\times 10^{5}\; Pa;
  • V shall be in cubic meters, \rm m^{3};
  • T = \rm 52.0 \textdegree C = (52.0 + 273.15)\; K = 325.15\; K.

Apply the ideal gas law:

\displaystyle \begin{aligned}V &= \frac{n\cdot R\cdot T}{P}\\ &= \frac{12.0\times 8.314\times 325.15}{5.00\times 10^{5}}\\ &= \rm 0.0649\; m^{3} \\ &= \rm (0.0649\times 10^{3})\; L \\ &=\rm 64.9\; L\end{aligned}.

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Answer:

Yes

Explanation:

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hope this helps
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3 years ago
Read 2 more answers
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