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ra1l [238]
4 years ago
9

Colorful fireworks often involve the decomposition of barium nitrate and potassium chlorate and the reaction of the metals magne

sium ,alminium and iron with oxygen.
(a)write the formulas of barium nitrate and potassium chlorate
(b)The decomposition of solid potassium chlorateleads to the formaion of solid potassium chloride and diatomic oxygen gas write an equation for the reaction
(c) The decomposition of the solid barium nitrate leads to the formation of solid barium oxide, nitrogen gas and diatomic oxygen gas
(d)write separate equations for the reactions of the solid Metals in magnesium aluminum with a diatomic oxygen gas to yield the corresponding metal oxide (Assume iron oxide contains Fe+ ions)
Chemistry
1 answer:
Fynjy0 [20]4 years ago
5 0

Fireworks owe their colors to reactions of combustion of the metals present. When Mg and Al burn, they emit a white bright light, whereas iron emits a gold light. Besides metals, oxygen is necesary for the combustion. The decomposition reactions of barium nitrate and potassium chlorate provide this element. At the same time, barium can burn emitting a green light.

(a) Barium nitrate is a <em>salt</em> formed by the <em>cation</em> barium Ba²⁺ and the <em>anion</em> nitrate NO₃⁻. Its formula is Ba(NO₃)₂. Potassium chlorate is a <em>salt</em> formed by the <em>cation</em> potassium K⁺ and the <em>anion</em> chlorate ClO₃⁻. Its formula is KClO₃.

(b) The balanced equation for the decomposition of potassium chloride is:

2KClO₃(s) ⇄ 2KCl(s) + 3O₂(g)

(c)  The balanced equation for the decomposition of barium nitrate is:

Ba(NO₃)₂(s) ⇄ BaO(s) + N₂(g) + 3O₂(g)

(d) The balanced equations of metals with oxygen to form metal oxides are:

  • 2 Mg(s) + O₂(g) ⇄ 2 MgO(s)
  • 4 Al(s) + 3 O₂(g) ⇄ 2 Al₂O₃(s)
  • 4 Fe(s) + 3 O₂(g) ⇄ 2 Fe₂O₃(s)

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In chemistry lab student is determining the salinity of seawater using a conductivity meter. The student made standards of NaCl
dimaraw [331]

Answer:

a. is an excel document. i uploaded as an attachment

b. concentration = 0.327

Explanation:

in the graph i uploaded for answer a, the x variable is conductivity,  while the y variable is % salinity.

the calculated regression line was calculated using excel =

y = 0.057655X - 0.00891

for answer part b,

we take x = 5.82

when we put this into the y formular

y = 0.057655(5.82) - 0.00891

y = 0.3355521 - 0.00891

y = 0.3266421

this is ≈ 0.327

in conclusion, using the standard curve, the concentration of unknown salt is 0.327. the % salinity = 0.327

6 0
3 years ago
The two major classes of telescopes are the _____ and the _____ telescope.
sukhopar [10]

Answer:

refractors and reflectors

Explanation:

4 0
3 years ago
Can someone please show me how to do problem number 4? Please show work so I can try to understand it. Thanks!
larisa86 [58]
With the given formula, we can calculate the amount of CO₂ using the balance equation but we first need the moles of CH₄

1) to find the moles of CH₄, we need to use the ideal gas formula (PV= nRT). if we solve for n, we solve for the moles of CH₄, and then we can convert to CO₂. Remember that the units put in this formula depending on the R value units. I remember 0.0821 which means pressure (P) has to be in atm, volume (V) in liters, the amount (n) in moles, and temperature (T) in kelvin.

PV= nRT

P= 1.00 atm
V= 32.0 Liters
n= ?
R= 0.0821 atm L/mol K
T= 25 C= 298 K

let plug the values into the formula.

(1.00 x 32.0 L)= n x 0.0821 x 298K

n= (1.00 x 32.0 L )/ (0.0821 x 298)= 1.31 moles CH₄

2) now let's convert the mole of CH₄ to moles to CO₂ using the balance equation

1.31 mol CH₄ (1 mol CO₂/ 1 mol CH₄)= 1.31 mol CO₂

3) Now let's convert from moles to grams using the molar mass of CO₂ (find the mass of each atom in the periodic table and add them)

molar mass CO₂= 12.00 + (2 x 16.0)= 44.0 g/mol

1.31 mol CO₂ ( 44.0 g/ 1 mol)= 57.6 g CO₂

Note: let me know if you any question.



5 0
4 years ago
In acidic solution, the nitrate ion can be used to react with a number of metal ions. One such reaction is NO3−(aq)+Sn2+(aq)→NO2
katrin [286]

Answer:

\boxed{\text{2, 1, 4, 2, 1, 2}}

Explanation:

NO₃⁻ + Sn²⁺ + __ → NO₂ + Sn⁴⁺ + __

Step 1: Separate into two half-reactions.

NO₃⁻ ⟶ NO₂

Sn²⁺ ⟶ Sn⁴⁺

Step 2: Balance all atoms other than H and O.

Done

Step 3: Balance O.

NO₃⁻ ⟶ NO₂ + H₂O

Sn²⁺ ⟶ Sn⁴⁺

Step 4: Balance H

NO₃⁻ + 2H⁺ ⟶ NO₂ + H₂O

Sn²⁺ ⟶ Sn⁴⁺

Step 5: Balance charge.

NO₃⁻ + 2H⁺ + e⁻ ⟶ NO₂ + H₂O

Sn²⁺ ⟶ Sn⁴⁺ + 2e⁻

Step 6: Equalize electrons transferred.

2 × [NO₃⁻ + 2H⁺ + e⁻ ⟶ NO₂ + H₂O]

1 × [Sn²⁺ ⟶ Sn⁴⁺ + 2e⁻]

Step 7: Add the two half-reactions.

2 × [NO₃⁻ + 2H⁺ + e⁻ ⟶ NO₂ + H₂O]

<u>1 × [Sn²⁺ ⟶ Sn⁴⁺ + 2e⁻]                                          </u>

     2NO₃⁻ + Sn²⁺ + 4H⁺ ⟶ 2NO₂ + Sn⁴⁺ + 2H₂O

Step 8: Check mass balance.

 On the left: 2 N, 6 O, 1 Sn, 4H

On the right: 2 N, 6 O, 1 Sn, 4H

Step 9: Check charge balance.

 On the left: -2 + 6 = +4

On the right: +4

The equation is balanced.

\text{The coefficients are }\boxed{\textbf{2, 1, 4, 2, 1, 2}}

4 0
4 years ago
A compound is formed when 171.2g of carbon reacts with 28.8 g of hydrogen what is the mass percent of hydrogen in the compound
PolarNik [594]
Hi.

You can calculate mass percent by dividing the mass by the total mass of the compound & multiplying by 100.

28.8 ÷ (171.2 + 28.8) = 0.144

0.144 · 100 = 14.4

I believe the mass percent of the hydrogen in the compound is 14.4%

~
5 0
3 years ago
Read 2 more answers
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