First, we shall calculate the total number of moles present in the final solution.
Number of moles in 0.50 m NaCl = molarity * volume = 0.50 * 3.0 = 1.5 moles.
Number of moles in 0.2777m NaCl = molarity * volume = 0.2777 * 9.0 = 0.24993 moles
Total number of moles = 1.5 + 0.24993 = 1.74993 moles
Second, we shall calculate the total volume of the final solution.
Total volume = 3 + 9 = 12 litres.
The molarity = total number of moles / total volume = 1.74993 / 12 = 0.1458 m
Answer:
ichedgepeth
Explanation:
beginner because it's tough than other things
Answer:
The answer to your question is: 25 g of PbCl2
Explanation:
Data
NaCl = 25 g
PbCl₂ = ?
Pb(NO3)2 + 2 NaCl ⇒ PbCl2 + NaNO3
MW NaCl = 58.5 g
MW PbCl2 = 277 g
2(58.5 g) of NaCl ------------------------ 277 g of PbCl2
25 g of NaCl ------------------------ x
x = (25 x 277) / 117
x = 25 g
Answer:
The 3rd option is correct
Explanation:
The element in group 13 and period 3 is aluminium which has the electron configuration
or [Ne] 3s^2 3p^1
