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Arada [10]
3 years ago
14

Would you define boiling point and melting point as a periodic table family trend (vertical groups), period trend (horizontal ro

ws), or neither? Explain your answer.
I am so stumped on this question please help me out. It does not help that my school did not give me a science book 
Chemistry
2 answers:
SSSSS [86.1K]3 years ago
8 0
Vertical groups I think as it increases and decreases down different groups
BartSMP [9]3 years ago
5 0
It's horizontal because, the periodic table goes horizontal
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0.50 mol A, 0.60 mol B, and 0.90 mol C are reacted according to the following reaction
algol [13]

Reactant C is the limiting reactant in this scenario.

Explanation:

The reactant in the balanced chemical reaction which gives the smaller amount or moles of product is the limiting reagent.

Balanced chemical reaction is:

A + 2B + 3C → 2D + E

number of moles

A = 0.50 mole

B = 0.60 moles

C = 0.90 moles

Taking A as the reactant

1 mole of A reacted to form 2 moles of D

0.50 moles of A will produce \frac{2}{1} = \frac{x}{0.50}

thus 0.50 moles of A will produce 1 mole of D

Taking B as the reactant

2 moles of B reacted to form 2 moles of D

0.60 moles of B reacted to form x moles of D

\frac{2}{2} = \frac{x}{0.6}

x = 2 moles of D is produced.

Taking C as the reactant:

3 moles of C reacted to form 2 moles of D

O.9 moles of C reacted to form x moles of D

\frac{2}{3} = \frac{x}{0.9}

= 0.60 moles of D is formed.

Thus C is the limiting reagent in the given reaction as it produces smallest mass of product.

5 0
3 years ago
Consider the oxidation of sodium metal to sodium oxide described by the balanced equation:
trapecia [35]

Answer:

1116g

Explanation:

We'll convert moles O2 -> moles of Na2O -> grams of Na2O.

Based on our balanced equation, we have 1 mole of O2 for every 2 moles of Na2O. This is our mole to mole ratio.

9 mol O2 x \frac{2 mol Na2O}{1 mol O2} = 18 mol Na2O

We can convert mols -> grams using the molar mass of Na2O- 62g.

18 mol Na2O x \frac{62g Na2O}{1 mol} = 1116g

4 0
3 years ago
Please help me I need to finish before my class is over
solniwko [45]

Number 3 is D

Number 4 is B

Number 5 is B

I think

6 0
3 years ago
Read 2 more answers
How many particles of CH4 are present in a 8.25 L sample of this gas?
Snowcat [4.5K]
Is this a mole question
4 0
3 years ago
Please help!
Misha Larkins [42]
Your answer is D, OH-! correct me if I’m wrong.
4 0
3 years ago
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