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lord [1]
3 years ago
6

W.

Chemistry
2 answers:
LenaWriter [7]3 years ago
8 0

Answer:

GOLD

Explanation:

The thermal conductivity of gold = 317 W/(m·K)

The thermal conductivity of berylium = 201 W/(m·K)

Inga [223]3 years ago
5 0

Answer:

answer willl be gold

Explanation:

bcz 1st highest thermal conductivity is having solver

then it is followed by copper , gold

so gold will be the answer

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Consider the following specific heats: copper, 0.384 J/g· ◦C; lead, 0.159 J/g· ◦C; water, 4.18 J/g· ◦C; glass, 0.502 J/g· ◦C. Wh
Roman55 [17]

Answer:

The correct answer is

2. Water

Explanation:

The specific heat capacity is the amount of heat required to raise the temperature of a unit mass of a substance by one degree. It is connected to the capacity of the substance to retain heat as well as the rate at which it will cool down or heat up when exposed to a specific amount of heat loss or heat supplied. A substance with a low heat capacity such as iron will cool down or heat up more quicker than a substance with a high heat capacity such as water.

From the list of substances water has the highest heat capacity, (4.18 J/g) as such it will retain heat for the longest period of time.

7 0
2 years ago
How long would it take the same amount of gaseous i2 to effuse from the same container under identical conditions?
77julia77 [94]

(46 sec) x √ ((253.80894 g I2/mol) / (44.0128 g N2O/mol)) = 110 sec

7 0
2 years ago
The standard cell potential (Eºcell) for the reaction below is +0.63 V. The cell potential
Likurg_2 [28]

Answer:

63.5 w isvthebanswerok is th answer

3 0
1 year ago
What volume of 0.4567 m h2so4 is required to neutralize 30.00 ml of 0.3210 m naoh?
sertanlavr [38]
Answer is: volume of H₂SO₄ is 42.1 mL.<span>
Chemical reaction: H</span>₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O.<span>
c(H</span>₂SO₄) = 0,4567 M = 0,4567 mol/L.<span>
V(NaOH) = 30 mL </span>÷ 1000 mL/L <span>= 0,03 L.
c(NaOH) = 0,321 M = 0,321 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,321 mol/L · 0,030 L.
n(NaOH) = 0,00963 mol.
From chemical reaction: n(H</span>₂SO₄) : n(NaOH) = 1 : 2.<span>
n(H</span>₂SO₄) = 0,01926 mol.<span>
V(H</span>₂SO₄) = n(H₂SO₄) ÷ c(H₂SO₄).<span>
V(H</span>₂SO₄) = 0,01926 mol ÷ 0,4567 mol/L.<span>
V(H</span>₂SO₄<span>) = 0,0421 L = 42,1 mL.</span>
3 0
2 years ago
Select only one most suitable description
Annette [7]
I believe it's a pure element
3 0
1 year ago
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