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telo118 [61]
3 years ago
13

A student is asked to convert measurements from liters to milliliters and from milliliters to liters. His answers are shown in b

old in the choices shown below. On which choice did he make a mistake?
Chemistry
2 answers:
Mumz [18]3 years ago
7 0

Answer:

he make a mistake in 3.6 L = 360 mL

Explanation:

As 1 L is equal to 1000 mL the correct convertion is

3.6L = 3600 mL

kirza4 [7]3 years ago
5 0
The answer is 3.6L=360mL
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They attract each other

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ArbitrLikvidat [17]

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5 0
2 years ago
How many moles are in 272 grams of hydrogen peroxide (H2O2) ?
Strike441 [17]

Answer:

8 moles

Explanation:

When we are asked to convert from grams of a substance into moles, we have to use the substance's molar mass.

Meaning that for this problem, we'll <em>use the molar mass of hydrogen peroxide</em> (H₂O₂), as follows:

  • 272 g ÷ 34 g/mol = 8 mol

There are 8 moles in 272 grams of hydrogen peroxide.

7 0
2 years ago
What is the mass, in grams, of
DIA [1.3K]

Answer:

The answers to your question are below

Explanation:

a) 6.85×1020 H2O2 molecules

H2O2   MW = 32 + 2 = 34 g

                                    34g -------------------- 6.023 x 10²³ molecules

                                    x       -------------------  6.85 x 10 ²⁰

                                   x = (6.85 x 10 ²⁰)(34)/  6.023 x 10²³

                                   x = 0.038 g

3.3×1022 SO2 molecules

MW SO2 = 32 + 32 = 64g

                                    64 g -------------------- 6.023 x 10²³ molecules

                                    x      --------------------  3.3×1022 SO2 molecules

                                    x = (3.3×1022 SO2)(64) / 6.023 x 10²³

                                   x = 3.51 g

5.5×1025 O3 molecules

MW = 16 x 3 = 48g

                                 48 g -----------------   6.023 x 10²³ molecules

                                  x     ------------------   5.5×1025 O3 molecules

                               x = (5.5×1025 )(48) /  6.023 x 10²³

                               x = 4383 g

9.30×1019 CH4 molecules

MW = 12 + 4 = 16 g

                              16 g --------------------  6.023 x 10²³ molecules

                              x      --------------------   9.30×1019 CH4 molecules

                           x = (9.30×1019)(16) / 6.023 x 10²³

                           x = 0.0025 g

4 0
3 years ago
A sample of CH4 is confined in a water manometer. The temperature of the system is 30.0 °C and the atmospheric pressure is 98.70
kakasveta [241]

Explanation:

The given data is as follows.

  P_{atm} = 98.70 kPa = 98700 Pa,  

      T = 30^{o}C = (30 + 273) K = 303 K

      height (h) = 30 mm = 0.03 m (as 1 m = 100 mm)

Density = 13.534 g/mL = 13.534 g/mL \times \frac{10^{6}cm^{3}}{1 m^{3}} \times \frac{1 kg}{1000 g}

                = 13534 kg/m^{3}

The relation between pressure and atmospheric pressure is as follows.

             P = P_{atm} + \rho gh

Putting the given values into the above formula as follows.

            P = P_{atm} + \rho gh

               = 98700 Pa + 13534 \times 9.81 \times 0.03 m

               = 102683.05 Pa

               = 102.68 kPa

thus, we can conclude that the pressure of the given methane gas is 102.68 kPa.

8 0
3 years ago
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