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Doss [256]
3 years ago
6

A sample of pure water is neutral because it contains 1. very few hydroxide ions and no hydronium ions. 2. no hydronium ions and

no hydroxide ions. 3. so few hydroxide and hydronium ions they cannot be detected. 4. very few hydronium ions and no hydroxide ions. 5. equal amounts of hydroxide and hydronium ions.
Chemistry
1 answer:
Nimfa-mama [501]3 years ago
3 0

Answer:

Option 5.

Equal amounts of hydroxide and hydronium ions

Explanation:

2H₂O  ⇄  H₃O⁺  +  OH⁻     Kw: 1×10⁻¹⁴

Neutral solution has pH = 7

So, [H₃O⁺] = [OH⁻]

In solutions of only pure water:

[H₃O⁺] = 1×10⁻⁷ M

[OH⁻] = 1×10⁻⁷ M

Kw = [H₃O⁺] . [OH⁻] → 1×10⁻⁷ . 1×10⁻⁷ = 1×10⁻¹⁴

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What is the Ksp of nickel(II) sulfide if the equilibrium concentrations of Ni2+ and S2− in a saturated solution of NiS are each
Ludmilka [50]
Dont know if its right but :/ <span>NiS <---> Ni+2 + S-2 </span><span>Ksp = [Ni+2] * [S-2] = (9.6E=11)^2 = 9.22E-21</span>
7 0
3 years ago
What is a chemical test to distinguish between the liquids hexane and hexene
WINSTONCH [101]

Hexane is alkane and hexene is alkene.


They can be distinguish by bromine test.


Hexane being a saturated hydrocarbon does not decolourizes Br2 in CCl4 and hexene being unsaturated ​ decolourizes Br2 in CCl4.


Reaction : CH3CH2CH2CH2CH2=CH2 + ​Br2 in CCl4 ------> CH3CH2CH2CH2CH2(Br)CH2Br ( colourless)



Read more on Brainly.in - https://brainly.in/question/2820606#readmore

6 0
4 years ago
For a particular reaction, ΔH∘=67.7 kJ/mol and ΔS∘=126.9 J/(mol⋅K). Assuming these values change very little with temperature, a
Sav [38]

Answer:

When T > 533.5K, the reaction is spontaneous in the forward reaction.

When T < 533.5K, the reaction is nonspontaneous

Explanation:

Using the equation:

ΔG = ΔH - TΔS

<em>Where T is absolute temperature</em>

<em />

The ΔG < 0 indicates nonspontaneus reaction, ΔG > 0 indicates spontaneous reaction.

That means:

0J/mol = 67700J/mol - T*126.9J/molK

T*126.9J/molK = 67700J/mol

T = 533.5 K

That means:

<h3>When T > 533.5K, the reaction is spontaneous in the forward reaction.</h3><h3>When T < 533.5K, the reaction is nonspontaneous</h3>

<em />

3 0
3 years ago
A 12​-liter ​[l] flask contains 1.3 moles​ [mol] of an ideal gas at a temperature of 20 degrees celsius ​[degrees​c]. What is th
Elden [556K]

Given: Volume of flask=12 L

Number of moles of an ideal gas=1.3 mol

Temperature=20°C

Gas is an ideal gas thus, it follows the ideal gas equation as follows:

PV=nRT

Here, P is pressure, V is volume, n is number of moles, R is Universal gas constant 0.0821 atm L K^{-1} mol^{-1} and T is temperature.

First convert temperature from °C to K as follows:

0 ^{o}C=273.15 K

Thus,

20 ^{o}C=293.15 K

Rearrange ideal gas equation to calculate pressure,

P=\frac{nRT}{V}

Putting the values,

P=\frac{(1.3 mol)(0.0821 atm L K^{-1}mol^{-1})(293.15 K)}{(12 L)}=2.6 atm

Therefore, pressure in the flask will be 2.6 atm.

3 0
4 years ago
URGENT
Sergio [31]

T = 2T , P = 2P as given in the question

Volume = mass *density

Now apply ideal gas law

PV=nRT

V = nRT/P

substitute value of V and P

V = nR2T/2P

V =nRT/P

mass*density = nRT/P

density will not change

4 0
3 years ago
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