Answer:
58.5 m
Explanation:
First of all, we need to find the total time the ball takes to reach the water. This can be done by looking at the vertical motion only.
The initial vertical velocity of the ball is
where
u = 21.5 m/s is the initial speed
is the angle
Substituting,
The vertical position of the ball at time t is given by
where
h = 13.5 m is the initial heigth
is the acceleration of gravity (negative sign because it points downward)
The ball reaches the water when y = 0, so
Which gives two solutions: t = 3.27 s and t = -0.84 s. We discard the negative solution since it is meaningless.
The horizontal velocity of the ball is
And since the motion along the horizontal direction is a uniform motion, we can find the horizontal distance travelled by the ball as follows:
Answer:
Speed is a "scalar" quantity
(C) is the correct answer
An object could travel at 10 m/s to some point and then return to the origin at 10 m/s for an average speed of 10 m/s, however it's displacement over that time would be zero for a net velocity of zero.
Momentum = mass * velocity
p = mv
p = 1.5 kg * 40 ms^-1
p = 60 kgm/s
To find components of a vector:
px = p * cos(theta)
px = 60 * cos(30)
px = 51.96 = 52 (rounded to two significant digits)
py = p * sin(theta)
py = 60 * sin(30)
py = 30
He initial momentum is 60kgm/s
The horizontal component is 52 kgm/s
The vertical component is 30 kgm/s
The pressure in a liquid at a given depth is called the hydrostatic pressure. This can be calculated using the hydrostatic equation:
P = ρgh
P = (1000 kg/m³)(9.8 m/s²)(4 m)
<h2>
P = 39200 Pa</h2>
