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shepuryov [24]
3 years ago
8

If you dropped a ball from a height of 10 m and measured its distance to the ground every 0.1 s, what would the graph of positio

n versus time look like?
a. It would curve upward.
b. It would curve downward.
c. It would be a straight line angled downward.
d. It would be a line parallel to the horizontal axis.
Physics
1 answer:
wlad13 [49]3 years ago
5 0

If you dropped a ball from any height, and measured its distance from the ground at any regular interval while it's falling, the graph of that distance versus time would be a graph that curves downward.

-- The ball is falling down.  As time goes on, it gets closer and closer to the ground.  Its remaining distance from the ground keeps decreasing, so the line on the graph slopes down.

-- The speed of the ball keeps increasing (it accelerates) because of the gravitational force on it. As time goes on, it covers more of the remaining distance during each interval than it did in the previous interval. The downward slope of the graph keeps increasing.

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3 years ago
It continues to fly along the same horizontal arc but increases its speed at the rate of 1.34 m/s 2 . Find the magnitude of acce
shepuryov [24]

This Question is not complete

Complete Question:

a. A hawk flies in a horizontal arc of radius 11.3 m at a constant speed of 5.7 m/s. Find its centripetal acceleration.

Answer in units of m/s2

b. It continues to fly along the same horizontal arc but increases its speed at the rate of 1.34 m/s2. Find the magnitude of acceleration under

these new conditions.

Answer in units of m/s2

Answer:

a. 2.875m/s²

b. 3.172m/s²

Explanation:

a. The formula for centripetal acceleration = (speed²) ÷ radius

Centripetal acceleration = (5.7m/s)²÷ 11.3m

Centripetal acceleration = 2.875m/s²

b. Magnitude of acceleration can be calculated by finding the sum of the vectors for the both the centripetal acceleration and the increase in the speed rate.

Centripetal acceleration ( acceleration x) = 2.875m/s²

Increase in the speed rate ( acceleration n) = 1.34m/s²

Magnitude of acceleration = √a²ₓ + a²ₙ

=√( 2.875m/s²)²+ (1.34m/s²)²

= √ 10.06m/s²

= 3.172m/s²

3 0
3 years ago
Read 2 more answers
2. A 2.5 meter-long wave travels at 1 m/s towards a fixed boundary. After 2 seconds, how does the wave appear?
Elan Coil [88]

Answer:

Since incident wave and its reflected part in opposite phase superimpose on each other

So correct answer will be

Option B

Explanation:

Here we know that the wave reflection is done by rigid boundary

So when wave is reflected by the boundary then its phase is reversed by 180 degree

so the reflected wave is in reverse phase from the boundary

so we can superimpose the reflected part with incident wave to dine the resultant wave

So the phenomenon is given as follow

6 0
3 years ago
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