Answer: Volcanoes and ridges are landforms that are created by the movement of tectonic plates.
Explanation:
Heat engines are less than 100% efficient because absolute zero cannot be reached
At the given erro in angle, the error in the measurement of sin 90 degrees would be 0.001.
<h3>
Percentage error</h3>
The percentage error of any measurement is obtained from the ratio of the error to the actual measurement.
The error of sin 90 degrees is calculated as follows;
sin 90 = 1
error in measurement = sin(90 - 0.5)
error in measurement = sin(89.5) = 0.999
<h3>Error in sin 90 degrees</h3>
Error in sin 90 degrees = 1 - 0.999
Error in sin 90 degrees = 0.001
Thus, at the given erro in angle, the error in sin 90 degrees would be 0.001.
Learn more about error in measurement here: brainly.com/question/26668346
1). c ... 2). d ... 3). a ... 4). d ... 5). c ... 6). a
7). b-mass ... c-m/s ... d-Newton's 1st ... e-Newton's 2nd
Answer:
The the linear speed (in m/s) of a point on the rim of this wheel at an instant=0.418 m/s
Explanation:
We are given that
Angular acceleration, ![\alpha=3.3 rad/s^2](https://tex.z-dn.net/?f=%5Calpha%3D3.3%20rad%2Fs%5E2)
Diameter of the wheel, d=21 cm
Radius of wheel,
cm
Radius of wheel, ![r=\frac{21\times 10^{-2}}{2} m](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B21%5Ctimes%2010%5E%7B-2%7D%7D%7B2%7D%20m)
1m=100 cm
Magnitude of total linear acceleration, a=![1.7 m/s^2](https://tex.z-dn.net/?f=1.7%20m%2Fs%5E2)
We have to find the linear speed of a at an instant when that point has a total linear acceleration with a magnitude of 1.7 m/s2.
Tangential acceleration,![a_t=\alpha r](https://tex.z-dn.net/?f=a_t%3D%5Calpha%20r)
![a_t=3.3\times \frac{21\times 10^{-2}}{2}](https://tex.z-dn.net/?f=a_t%3D3.3%5Ctimes%20%5Cfrac%7B21%5Ctimes%2010%5E%7B-2%7D%7D%7B2%7D)
![a_t=34.65\times 10^{-2}m/s^2](https://tex.z-dn.net/?f=a_t%3D34.65%5Ctimes%2010%5E%7B-2%7Dm%2Fs%5E2)
Radial acceleration,![a_r=\frac{v^2}{r}](https://tex.z-dn.net/?f=a_r%3D%5Cfrac%7Bv%5E2%7D%7Br%7D)
We know that
![a=\sqrt{a^2_t+a^2_r}](https://tex.z-dn.net/?f=a%3D%5Csqrt%7Ba%5E2_t%2Ba%5E2_r%7D)
Using the formula
![1.7=\sqrt{(34.65\times 10^{-2})^2+(\frac{v^2}{r})^2}](https://tex.z-dn.net/?f=1.7%3D%5Csqrt%7B%2834.65%5Ctimes%2010%5E%7B-2%7D%29%5E2%2B%28%5Cfrac%7Bv%5E2%7D%7Br%7D%29%5E2%7D)
Squaring on both sides
we get
![2.89=1200.6225\times 10^{-4}+\frac{v^4}{r^2}](https://tex.z-dn.net/?f=2.89%3D1200.6225%5Ctimes%2010%5E%7B-4%7D%2B%5Cfrac%7Bv%5E4%7D%7Br%5E2%7D)
![\frac{v^4}{r^2}=2.89-1200.6225\times 10^{-4}](https://tex.z-dn.net/?f=%5Cfrac%7Bv%5E4%7D%7Br%5E2%7D%3D2.89-1200.6225%5Ctimes%2010%5E%7B-4%7D)
![v^4=r^2\times 2.7699](https://tex.z-dn.net/?f=v%5E4%3Dr%5E2%5Ctimes%202.7699)
![v^4=(10.5\times 10^{-2})^2\times 2.7699](https://tex.z-dn.net/?f=v%5E4%3D%2810.5%5Ctimes%2010%5E%7B-2%7D%29%5E2%5Ctimes%202.7699)
![v=((10.5\times 10^{-2})^2\times 2.7699)^{\frac{1}{4}}](https://tex.z-dn.net/?f=v%3D%28%2810.5%5Ctimes%2010%5E%7B-2%7D%29%5E2%5Ctimes%202.7699%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D)
![v=0.418 m/s](https://tex.z-dn.net/?f=v%3D0.418%20m%2Fs)
Hence, the the linear speed (in m/s) of a point on the rim of this wheel at an instant=0.418 m/s