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3 years ago

6

1. Identify this mystery element: I am very reactive, I desperately want to get rid of my electron. When I make a compound with

Chlorine it is table salt. Who am I? 2. Identify this mystery element. I am amazing and have no cares in the world. I don’t like to form bonds because frankly, I am so perfect. I was very popular in Las Vegas by making lights very bright and colorful.

2 answers:

galina1969 [7]3 years ago

8 0

1.) NaCl (Sodium Chlorine)
2.) Ne (Neon) lights.

sladkih [1.3K]3 years ago

5 0

1) You are Sodium
2) You are Neon

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Answer:

Explanation:

Given

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$\lambda _2=589.6 nm$

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where h=Planck's constant

x=velocity of Light

$\lambda$ =wavelength of emission

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If it takes you 10 seconds to increase from 0 km/h to 50 km/h, what is your acceleration?

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3 years ago

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A linear accelerator produces a pulsed beam of electrons. The pulse current is 0.50 A, and the pulse duration is 0.10 μs. (a) Ho

Crank

Answer:

a)N = 3.125 * 10¹¹

b) I(avg) = 2.5 × 10⁻⁵A

c)P(avg) = 1250W

d)P = 2.5 × 10⁷W

Explanation:

Given that,

pulse current is 0.50 A

duration of pulse Δt = 0.1 × 10⁻⁶s

a) The number of particles equal to the amount of charge in a single pulse divided by the charge of a single particles

N = Δq/e

charge is given by Δq = IΔt

so,

N = IΔt / e

$N = \frac{(0.5)(0.1 * 10^-^6)}{(1.6 * 10^-^1^9)} \\= 3.125 * 10^1^1$

N = 3.125 * 10¹¹

b) Q = nqt

where q is the charge of 1puse

n = number of pulse

the average current is given as I(avg) = Q/t

I(avg) = nq

I(avg) = nIΔt

= (500)(0.5)(0.1 × 10⁻⁶)

= 2.5 × 10⁻⁵A

C) If the electrons are accelerated to an energy of 50 MeV, the acceleration voltage must,

eV = K

V = K/e

the power is given by

P = IV

P(avg) = I(avg)K / e

$P(avg) = \frac{(2.5 * 10^-^5)(50 * 10^6 . 1.6 * 10^-^1^9)}{1.6 * 10^-^1^9}$

= 1250W

d) Final peak=

P= Ik/e

= $= P(avg) = \frac{(0.5)(50 * 10^6 . 1.6 * 10^-^1^9)}{1.6 * 10^-^1^9}\\2.5 * 10^7W$

P = 2.5 × 10⁷W

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3 years ago

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