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dmitriy555 [2]
3 years ago
10

the area of a triangle is 36 sq. inches. if the base of the triangle is 6 inches, what is its height? a. 15 inches b. 6 inches c

. 3 inches d. 12 inches
Mathematics
2 answers:
inessss [21]3 years ago
8 0
A=1/2bh
b=6
a=36
36=1/2(6)(h)
36=3h
divide both sides by 3
12=h

height=12 inches

answer is D
Elodia [21]3 years ago
5 0

Answer:

Option (d) is correct.

The height of given triangle is 12 inches.

Step-by-step explanation:

Given: The area of a triangle is 36 sq. inches. and the base of the triangle is 6 inches.

We have to find the height of the triangle.

We know,

Area of triangle = \frac{1}{2} \times base\times height

Rearrange for height

Multiply both side by \frac{2}{base}

We get,

\text{Area of triangle}\times \frac{2}{base}=height

Given : Area = 36 inches²

and base = 6 inches

substitute, we have,

36\times \frac{2}{6}=height

Simplify, we have,

Height = 12 inches

Thus, The height of given triangle is 12 inches.

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%2F7%7D%7B7%5Csqrt%7B10%7D%2F2%20%7D" id="TexFormula1" title="\frac{3/7}{7\sqrt{10}
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\dfrac{\dfrac37}{\dfrac{7\sqrt{10}}2}\times\dfrac{14}{14}=\dfrac{3\times2}{7\sqrt{10}\times7}=\dfrac6{49\sqrt{10}}

Rationalize the denominator by multiplying both numerator and denominator by √10:

\dfrac6{49\sqrt{10}}\times\dfrac{\sqrt{10}}{\sqrt{10}}=\dfrac{6\sqrt{10}}{49(\sqrt{10})^2}=\dfrac{6\sqrt{10}}{49\times10}=\dfrac{6\sqrt{10}}{490}

Lastly, cancel the common factor of 2 in both the numerator and denominator (which comes from 6 = 2×3 and 490 = 2×245):

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<h3>How to add fractions</h3><h3 />

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Therefore, the sum of 6/7 and 1/2 is 19/14

Learn more about fraction:

brainly.com/question/11562149

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