What is the movement of ocean crust called

1 answer:

8 0

<em>The movenment of the oceanic crust is called continenetal drift. It was discovered by Alfred Wegener. A German scientist in the 18th centuries. He discovered Pangea. Otherwise called " Theory of Continental Drift".

I'm glad to help. :)</em>

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The ray diagram shows a vase that is placed beyond the center of curvature of a concave mirror. Which best describes how the ima

Law Incorporation [45]

To get to know the characteristics of the image formed, you complete the ray diagram.
When the object is place beyond C the image formed is usual smaller than the object.
The image is also inverted.
∴The best statement that describes the image is <span>D.) It will be smaller than the vase and inverted</span>

3 0

3 years ago

Read 2 more answers

488 J of work is done to a box which is moved across the floor for a distance of 8.9 m. What net force is required to act on the

kvv77 [185]

According to the formula
$a = f \times d$
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8 0

4 years ago

Compare the time period of two simple pendulums of length 4m and 16m at a place.

Vlad1618 [11]

Answer:

the period of the 16 m pendulum is twice the period of the 4 m pendulum

Explanation:

Recall that the period (T) of a pendulum of length (L) is defined as:

$T=2\,\pi\,\sqrt{ \frac{L}{g} }$

where "g" is the local acceleration of gravity.

SInce both pendulums are at the same place, "g" is the same for both, and when we compare the two periods, we get:

$T_1=2\,\pi\,\sqrt{\frac{4}{g} } \\T_2=2\,\pi\,\sqrt{\frac{16}{g} } \\ \\\frac{T_2}{T_1} =\sqrt{\frac{16}{4} } =2$

therefore the period of the 16 m pendulum is twice the period of the 4 m pendulum.

5 0

3 years ago

The relative density of oxygen and carbon dioxide are 16, 12 respectively. If 25cm3 of carbon dioxide effuse out in 75 sec what

Mrac [35]

Answer:

32 cm³

Explanation:

The given gas data are;

The relative density of oxygen = 16

The relative density of carbon dioxide = 12

The time it takes 25 cm³ of carbon dioxide to effuse out = 75 seconds'

The duration of effusion of the oxygen = 96 seconds

The rate of effusion of carbon dioxide, R1 = 25 cm³/(75 sec) = (1/3) cm³/sec

According to Graham's law of diffusion and effusion of a gas, we have;

$\dfrac{Rate \ of \ effudion \ of \ gas \ 1}{Rate \ of \ effudion \ of \ gas \ 2} =\dfrac{The \ relative \ density \ of \ gas \ 2}{The \ relative \ density \ of \ gas \ 1}$