We are given
V = 100 V
R = 500 Ω
C = 10^4 F
q(0) = 0
We are asked to find the charge q(t) of the RC capacitor.
To solve this, we use the formula:
q(t) = CV [1 - e^(-t/RC) ]
Substituting thet given values
q(t) = 10^4 (100) [1 - e^(-t/500(10^4) ]
q(t) = 1 x 20^6 [1 - e^(-2x10^7 t) ]
Since we only asked to get the charge q(t) in terms of t, the answer is
q(t) = 1 x 20^6 [1 - e^(-2x10^7 t) ]
Answer:
C.....im just typing more now because of the rule that it has to be 20 characters long
Answer:
Explanation:
Given,
Radius R = 6 feet
Height H = 9 feet
Depth of the water = 5 feet
Volume of right circular cylinder,
Differentiate with respect to the H
Now,
Hence, the rate of chage of height of water is 0.044 feet per min.
Answer:
B.) Genes are segments of DNA, which is packaged in chromosomes.
Explanation: trust the process.
BUDDY.
The velocity of the two balls after the collision is 0.73 m/s.
The velocity of the two balls after the collision can be calculated using the formula below.
<h3>Formula:</h3>
- mu+m'u' = V(m+m')............... Equation 1
<h3>Where:</h3>
- m = mass of the first ball
- m' = mass of the second ball
- u = initial velocity of the first ball
- u' = initial velocity of the second ball
- V = velocity of the two balls after the collision.
make V the subject of the equation
- V = (mu+m'u')/(m+m')................ Equation 2
From the question,
<h3>Given:</h3>
- m = 0.25 kg
- m' = 0.3 kg
- u = 1 m/s
- u' = 0.5 m/s
Substitute these values into equation 2
- V = [(0.25×1)+(0.3×0.5)](0.25+0.3)
- V = 0.4/0.55
- V = 0.73 m/s.
Hence, the velocity of the two balls after the collision is 0.73 m/s
Learn more about collision here: brainly.com/question/7694106