Answer:
b. 0.20 m/s.
Explanation:
Given;
initial mass, m = 0.2 kg
maximum speed, v = 0.3 m/s
The total energy of the spring at the given maximum speed is calculated as;
K.E = ¹/₂mv²
K.E = 0.5 x 0.2 x 0.3²
K.E = 0.009 J
If the mass is changed to 0.4 kg
¹/₂mv² = K.E
mv² = 2K.E
Therefore, the maximum speed is 0.20 m/s
Answer:
30N in the direction the 45N acts.
Explanation:
Fnet = F1 + F2 (the vector sum of the forces)
Assigning a positive direction to the 45N force and a negative direction to the 15N force gives:
Fnet = 45 - 15
Fnet = 30N
Since the answer is positive, it is in the direction the 45N force acts.
Answer:
1,1 m
Explanation:
Dado que;
coeficiente de fricción = 0,6
sabemos que W = R = mgcos 37 = 3.5Kg * 10m / s ^ 2 * cos37 = 27.95 N
coeficiente de fricción = fuerza / reacción normal (R)
Fuerza = 0.6 * 27.95 N
Fuerza (F) = 16.77 N
Recuerda que F = Ke
dónde;
K = constante de fuerza (15N / m)
e = extensión (lo desconocido)
e = F / K
e = 16,77 N / 15 N / m
e = 1,1 m
Answer:
I have answer with explanations in each of the six (6) special cases.
Explanation:
Please find attached the detailed solution to all your questions.
