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3 years ago

What body in the solar system do you think is one focus of the moons orbit

2 answers:

6 0

-- From the point of view of an observer on Earth, the moon's orbit is an ellipse
with the Earth's center at one focus.

-- From the point of view of an observer on the sun, or on any other planet,
the moon's orbit is an ellipse with the sun at one focus, and perturbed by being
near the Earth.

stiks02 [169]3 years ago

6 0

The Earth.

Orbits are elliptical in shape with the body being orbited at one focus. So the Sun is at one focus of the Earth's orbit around it.

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When positively charged particles were radiated onto a gold atom, a few of the particles bounced back. Which of the following ca

ratelena [41]

Positively charged protons in the nucleus of the gold atom .... rutherford scattering ???

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3 years ago

Read 2 more answers

The Hawaiian hot spot sits below the Pacific plate. As the plate moves over the hot spot, a chain of volcanoes is formed. The Ea

Viktor [21]

Answer:

$3.2048179721\times 10^{-9}\ m/s$

Explanation:

Assuming that the pacific plate moved 178 km in 1.76 million years.

s = Distance = 178 km

t = Time taken = 1.76 million years

Speed is given by

$v=\dfrac{s}{t}\\\Rightarrow v=\dfrac{178000}{1.76\times 10^6\times 365.25\times 24\times 3600}\\\Rightarrow v=3.2048179721\times 10^{-9}\ m/s$

The speed of the plate is $3.2048179721\times 10^{-9}\ m/s$

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2 years ago

WILL GIVE BRAINLIEST!!!!!!

DENIUS [597]

Answer: option d: The nucleus of Atom Q is more stable than the nucleus of Atom P.

Explanation:

Atom P is radioactive and disintegrates, it emits beta particles (high speed electrons or positrons) because it is not stable. On disintegration, it forms a stable Atom Q which is non-radioactive and thus it does not disintegrates further.

Thus, the correct option is only d. The nucleus of Atom Q is more stable than the nucleus of Atom P.

8 0

2 years ago

Choose the sequence of energy forms that best fits each item

castortr0y [4]

I hope its help for you

have a great day

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2 years ago

Suppose you spray your sister with water from a garden hose. The water is supplied to the hose at a rate of 0.625×10−3 m3/s and

Tems11 [23]

Answer:

0.153 m/s

Explanation:

The flowrate Q = 0.625 x 10-3 m^3-/s

The diameter of the nozzle d = 5.19 x 10^-3 m

the velocity V = ?

The cross-sectional area of the flow A = $\pi d^{2}/4$

==> (3.142 x 5.19 x 10^-3)/4 = 4.077 x 10^-3 m^2

From the continuity equation,

Q = AV

V = Q/A = (0.625 x 10-3)/(4.077 x 10^-3) = 0.153 m/s

4 0

3 years ago