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Mademuasel [1]
3 years ago
13

What body in the solar system do you think is one focus of the moons orbit

Physics
2 answers:
PolarNik [594]3 years ago
6 0

-- From the point of view of an observer on Earth, the moon's orbit is an ellipse
with the Earth's center at one focus.

-- From the point of view of an observer on the sun, or on any other planet,
the moon's orbit is an ellipse with the sun at one focus, and perturbed by being
near the Earth.


stiks02 [169]3 years ago
6 0
The Earth.

Orbits are elliptical in shape with the body being orbited at one focus. So the Sun is at one focus of the Earth's orbit around it.
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A roller coaster has a mass of 450 kgIt sits at the top of a hill with height 49 m. If it drops from this hill, how fast is it g
fgiga [73]

The speed of the roller coater at the bottom of the hill is 31 m/s.

<h3>Speed of the roller coater at the bottom of the hill</h3>

Apply the principle of conservation of mechanical energy as follows;

K.E(bottom) = P.E(top)

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

  • v is the speed of the coater at bottom hill
  • h is the height of the hill
  • g is acceleration due to gravity

v = √(2 x 9.8 x 49)

v = 31 m/s

Thus, the speed of the roller coater at the bottom of the hill is 31 m/s.

Learn more about speed here: brainly.com/question/6504879

#SPJ1

6 0
2 years ago
In general, metalloids are slightly reactive.
algol [13]
Yes, in general, metalloids are slightly reactive.
6 0
4 years ago
Read 2 more answers
A closed system’s internal energy changes by 178 J as a result of being heated with 658 J of energy.
statuscvo [17]
Internal energy of the system changes by ΔE = 178 J.
Heat given to the system = Q = +658 J.

According to the first law of thermodynamics, 
ΔE = Q + W
178 = 658 + W 
∴ W = 178-658 = -480 J

Minus sign indicates that work is done by the system. 
7 0
3 years ago
Read 2 more answers
A cannonball is fired at a 45.0° angle and an initial velocity of 670 m/s. Assume no air resistance. What is the vertical compon
elixir [45]

Answer:

<h3>473.8 m/s; 473.8 m/s</h3>

Explanation:

Given the initial velocity U = 670m/s

Horizontal velocity Ux = Ucos theta

Vertical component of the cannon velocity Uy = Usin theta

Given

U = 670m/s

theta = 45°

horizontal component of the cannonball’s velocity = 670 cos 45

horizontal component of the cannonball’s velocity = 670(0.7071)

horizontal component of the cannonball’s velocity = 473.757m/s

Vertical component of the cannonball’s velocity = 670 sin 45

Vertical component of the cannonball’s velocity  = 670 (0.7071)

Vertical component of the cannonball’s velocity  = 473.757m/s

Hence pair of answer is 473.8 m/s; 473.8 m/s

6 0
3 years ago
13. You push with 56 N on a 15-kg box, and there is a 23-N force of friction. How fast will the box accelerate?
Flura [38]

Answer:

The acceleration is 2.2 m/s^2

Explanation:

In the attached image, we can see the free body diagram. And using the second law of Newton it will be possible to find the acceleration of the box.

4 0
3 years ago
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