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2 years ago

Assuming a constant force if the mass of an object increases the acceleration of the object will

Physics

1 answer:

oksano4ka [1.4K]2 years ago

6 0

Answer:

The accelaration will decrease because force is inversly proportional to mass.

Explanation:

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When monochromatic light passes through the interface between two unknown materials at an angle θ where 0∘<θ<90∘, no chang

kirill115 [55]

Answer:

the correct one is the first, the refractive index of the two materials must be the same

Explanation:

When a beam of light passes through two materials, it must comply with the law of refraction

n₁ sin θ₁ = n₂ sin θ₂

where n₁ and n₂ are the refractive indices of each medium.

In this case, it indicates that the light does not change direction, so the input and output angle of the interface must be the same,

θ₁ = θ₂ = θ

substituting

n₁ = n₂

therefore the refractive index of the two materials must be the same

When reviewing the answers, the correct one is the first

5 0

2 years ago

The resistance of a wire is not dependent on

Komok [63]

d. Current

It is opposing

3 0

3 years ago

During takeoff, a plane goes from 0 to 50 m/s in 8s. What is its acceleration? Halos fast is it going after 5 s? How far had it

svlad2 [7]

A= 50/8 m/s^2

vf=at=50/8 * 5= 250/8 m/s at t=5sec 

time to get to 50m/s 
50=50/8*t or t=8 seconds 
distance=1/2 a t^2=1/2 50/8 64 
distance= 400 m check that.

4 0

2 years ago

Read 2 more answers

Three moles of an ideal gas with a molar heat capacity at constant volume of 4.9 cal/(mol∙K) and a molar heat capacity at consta

Sergeu [11.5K]

Answer:

The heat flows into the gas during this two-step process is 120 cal.

Explanation:

Given that,

Number of moles = 3

Heat capacity at constant volume = 4.9 cal/mol.K

Heat capacity at constant pressure = 6.9 cal/mol.K

Initial temperature = 300 K

Final temperature = 320 K

We need to calculate the heat flow in to gas at constant pressure

Using formula of heat

$\Delta H_{1}=nC_{p}\times\Delta T$

Put the value into the formula

$\Delta H_{1}=3\times6.9\times(320-300)$

$\Delta H_{1}=414\ cal$

We need to calculate the heat flow in to gas at constant volume

Using formula of heat

$\Delta H_{1}=nC_{v}\times\Delta T$

Put the value into the formula

$\Delta H_{1}=3\times4.9\times(300-320)$

$\Delta H_{1}=-294\ cal$

We need to calculate the heat flows into the gas during two steps

Using formula of total heat

$\Delta H_{T}=\Delta H_{1}+\Delta H_{2}$

$\Delta H_{T}=414-294$

$\Delta H_{T}=120\ cal$

Hence, The heat flows into the gas during this two-step process is 120 cal.

7 0

3 years ago

HURRY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

OLga [1]

At the top, due to the fact that POTENTIAL energy is Stored energy.

5 0

3 years ago

Read 2 more answers