Refer to the diagram shown below.
The basket is represented by a weightless rigid beam of length 0.78 m.
The x-coordinate is measured from the left end of the basket.
The mass at x=0 is 2*0.55 = 1.1 kg.
The weight acting at x = 0 is W₁ = 1.1*9.8 = 10.78 N
The mass near the right end is 1.8 kg.
Its weight is W₂ = 1.8*9.8 = 17.64 N
The fulcrum is in the middle of the basket, therefore its location is
x = 0.78/2 = 0.39 m.
For equilibrium, the sum of moments about the fulcrum is zero.
Therefore
(10.78 N)*(0.39 m) - (17.64 N)*(x-0.39 m) = 0
4.2042 - 17.64x + 6.8796 = 0
-17.64x = -11.0838
x = 0.6283 m
Answer: 0.63 m from the left end.
1.25 is the answer to tht if im right but could be wrong
The statement is true because an object will remain not moving until an external force is applied into. so in order to move an object external force should be applied. for example an object fell down, even no one pushes it pulls it, but the force due to gravity is acting on it so there is still a force acting on it.
Answer:since time goes to the right you look at the lines that are most pointed to the right with less distance so that would be B, A, D, C
Explanation:
The runner's acceleration depends on the net force acting on him.
His acceleration is going to be ...
(net force on him, in Newtons) divided by (80 kg) .
The unit of the acceleration is meters/second-squared .
The direction of the acceleration is the same as the direction
of the net force.