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barxatty [35]
2 years ago
14

Calculate the efficiency of a light bulb that gives 40J of light from 200J of electrical energy’s

Physics
1 answer:
nekit [7.7K]2 years ago
7 0

Answer:

This formula is the most common one used. The efficiency is in a %

20%

Explanation:

Efficiency = energy out / energy in * 100 (for a %)

Efficiency = 40 / 200 * 100

Efficiency = 20%

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Vsevolod [243]
<span>node spacing = half of wavelength = 3 cm velocity = 10 cm/s = freq * wavelength hench freq = 10/6 = 5/3 = 1.7 hz</span>
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If two objects have the same volume but one has a greater mass, the one with greater mass
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Explain more. I can't understand

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A rocket passes you at a speed of 0.85c, and you measure its length to be 35.0 m. What is its measured length when at rest?
viktelen [127]

Answer:

66.4 m

Explanation:

To solve the problem, we can use the length contraction formula, which states that the length observed in the reference frame moving with the object (the rocket) is given by

L=L_0 \sqrt{1-(\frac{v}{c})^2}

where

L_0 is the proper length (the length measured from an observer at rest)

v is the speed of the object (the rocket)

c is the speed of light

Here we know

v = 0.85c

L = 35.0 m

So we can re-arrange the equation to find the length of the rocket at rest:

L_0 = \frac{L}{\sqrt{1-(\frac{v}{c})^2}}=\frac{35.0}{\sqrt{1-(\frac{0.85c}{c})^2}}=66.4 m

8 0
3 years ago
Describe a technology used in space exploration.
Alex777 [14]

Answer:

High speed optical communication technology

To be able to communicate from the space to the earth and from earth to space is one of the most essential features required during space exploration.

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Space exploration involves going into the space, beyond the earth's atmosphere. Landing on other planets and studying their details, going into deeper space beyond the planets to discover new cosmic events or structures is all a part of space exploration.

The key to analyse the studies and observations is being able to communicate the data collected, photos taken etc to the launch centers or space centers on earth. The space centers on earth should also be able to communicate with the persons or the satellites in space.

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3 years ago
Three collinear forces,F1=45N west,F2=63N east and an unknown force F3 are applied to an object.The resultant force of the three
Greeley [361]

Take east to be the positive direction. Then the resultant force from adding <em>F</em>₁ and <em>F</em>₂ is

<em>F</em>₁ + <em>F</em>₂ = (-45 N) + 63 N = 18 N

which is positive, so it's directed east.

To this we add a third force <em>F</em>₃ such that the resultant is 12 N pointing west, making it negative, so that

18 N + <em>F</em>₃ = -12 N

<em>F</em>₃ = -30 N

So <em>F</em>₃ has a magnitude of 30 N and points west.

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