E = mc²
E = 0.235 kg · (3×10⁸ m/s)² = 0.235 · 9×10¹⁶ kg·m/s²
E = 2.115×10¹⁶ J
The answer is d) 2.12×10¹⁶ J
Answer:
Explanation:
Given
height of building h=3 m
Landing velocity of diver
at an angle of 
Let u be the initial velocity of diver at an angle of \theta with horizontal
Since there is no acceleration in horizontal direction therefore horizontal component of velocity will remain same
---- -----1
Considering Vertical motion

here 




----------------2
Divide 2 and 1 we get



Thus 

Answer:
false
Explanation:
every object will always have the force of gravity acting upon it.
The second one is correct not sure about the first one sorry