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OleMash [197]
2 years ago
10

When a net force of 17.0 newtons is applied to a dictionary placed on a frictionless table, it accelerates by 3.75 meters/second

Æ. What is the mass of the book?
Physics
1 answer:
4vir4ik [10]2 years ago
8 0
Force = (mass) x (acceleration)    (Newton's second law of motion)

Divide both sides of the equation by 'acceleration', and you have

Mass = (force) / (acceleration)

Mass = 17 newtons / 3.75 meters per second-sqrd = 4.533 kilograms (rounded)
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In billiards, the 0.165 kg cue ball is hit toward the 0.155 kg eight ball, which is stationary. The cue ball travels at 5.8 m/s
Damm [24]

Answer:

another ball velocity = 3.92 m/s and with 30° clockwise from initial direction

Explanation:

given data

mass m1 = 0.165 kg

mass m2 = 0.155 kg

before collision velocity v1 = 5.8 m/s

before collision velocity v2 = 0

angle =  35.0° from initial direction

after collision 1st ball velocity v3 = 3.2 m/s

to find out

after collision another ball velocity v4

solution

we consider here ball move in x axis and after collision 1st ball move upside of x axis with angle 35 degree and other ball move downside with x axis with angle θ

so from conservation of momentum we say

m1v1 = m1v3cos35 + m2v4cosθ   with x axis    .............1

m1v3sin35 = m2v4sinθ                   with y axis  .............2

so from 1 equation

0.165 × 5.8 = 0.165(3.2)cos35 + 0.155(v4)cosθ

v4 cosθ  = 3.38                                            .................3

form 2 equation

0.165(3.2)sin35 = 0.155(v4)sinθ  

v4 sinθ = 1.95                                              ......................4

so magnitude of another ball velocity is square and adding equation 3 and 4

another ball velocity = √(3.39²+1.96²)

another ball velocity = 3.92 m/s

and direction is tanθ = 1.96/3.39

θ = 30° clockwise from initial direction

3 0
3 years ago
Bicyclists in the Tour de France do enormous amounts of work during a race. For example, the average power per kilogram generate
tigry1 [53]

Explanation:

It is given that,

Average power per unit mass generated by Lance, \dfrac{P}{m}=6.5\ W/kg

P=6.5\times 75=487.5\ W

(a) Distance to cover race, d = 160\ km =160\times 10^3\ m

Average speed of the person, v = 11 m/s

If t is the time taken to cover the race.

t=\dfrac{d}{v}

t=\dfrac{160\times 10^3\ m}{11\ m/s}

t = 14545.46 s

Let W is the work done. The relation between the work done and the power is given by :

P=\dfrac{W}{t}

W=P\times t

W=487.5\times 14545.46

W = 7090911.75 J

(b) Since, 1\ J=2.389\times 10^{-4}\ calories

So, in 7090911.75 J, W=7090911.75 \times 2.389\times 10^{-4}

W = 1694.01 J

Hence, this is the required solution.

6 0
3 years ago
A 1.50-V battery supplies 0.414 W of power to a small flashlight. If the battery moves 4.93 1020 electrons between its terminals
slamgirl [31]

Answer:

2.86×10⁻¹⁸ seconds

Explanation:

Applying,

P = VI................ Equation 1

Where P = Power, V = Voltage, I = Current.

make I the subject of the equation

I = P/V................ Equation 2

From the question,

Given: P = 0.414 W, V = 1.50 V

Substitute into equation 2

I = 0.414/1.50

I = 0.276 A

Also,

Q = It............... Equation 3

Where Q = amount of charge, t = time

make t the subject of the equation

t = Q/I.................. Equation 4

From the question,

4.931020 electrons has a charge of (4.931020×1.6020×10⁻¹⁹) coulombs

Q = 7.899×10⁻¹⁹ C

Substitute these value into equation 4

t =  7.899×10⁻¹⁹/0.276

t = 2.86×10⁻¹⁸ seconds

5 0
3 years ago
Why did Kenyatta want to distance himself from the Mau Mau? Check all that apply.
Savatey [412]

Answer:

B and C!

Explanation:

I just did it on edge. I hope this helps!

3 0
3 years ago
What gases can CFC and HCFC refrigerants decompose into at high temperatures
nekit [7.7K]

Answer:

Hydrochloric and Hydrofluoric Acids.

3 0
2 years ago
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