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vova2212 [387]
3 years ago
9

How do you calculate the total resistance of a series circuit

Physics
1 answer:
CaHeK987 [17]3 years ago
5 0
Add all the resistances across the circuit together the calculate the total resistance
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Define anterior and posterior in correlation to the body. (ANATOMY)
tatyana61 [14]

Answer:

it should be right it's from go.ogle hm!!!

Explanation:

Anterior or ventral - front (example, the kneecap is located on the anterior side of the leg). Posterior or dorsal - back (example, the shoulder blades are located on the posterior side of the body). Medial - toward the midline of the body (example, the middle toe is located at the medial side of the foot).

8 0
3 years ago
Read 2 more answers
What is the median of 5 12 7 15 3 6 1
xxMikexx [17]

Answer:

6

Explanation:

The median is found by listing the numbers in order numerically and finding the one that is right in the middle. In this case you have 1, 3, 5, 6, 7, 12, 15 where the middle term is 6.

7 0
3 years ago
Number of complete 90.9 MHz radio waves over a 1.50 km distance
zimovet [89]
You could answer this right away IF you knew the length of each wave, right ?

Well,  Wavelength = (speed) / (frequency).

Speed = 3 x 10⁸ m/s  (the speed of light)
and
Frequency = 90.9 x 10⁶ Hertz.

So the length of each wave is  3 x 10⁸ / 90.9 x 10⁶  meters.

To answer the question, see how many pieces you have to cut
that 1.5 km into, in order for each piece to be 1 wavelength. 
It'll be

(1,500 meters) divided by (3 x 10⁸ meters/sec) / (90.9 x 10⁶ Hz)

To divide by a fraction, flip the fraction and then multiply:

(1500 meters) times (90.9 x 10⁶ Hz)/(3 x 10⁸ meters/sec)

=   454.5
5 0
4 years ago
Convert 1.3 km to m
a_sh-v [17]

Answer: 1300m

Explain: from km to m times 1000

8 0
3 years ago
An unknown radioactive sample is observed to decrease in activity by a factor of two in a one hour period. What is its half-life
elena55 [62]

Answer:

The half-life is t_{1/2} = 1.005 h

Explanation:

Using the decay equation we have:

A=A_{0}e^{-\lambda t}

Where:

  • λ is the decay constant
  • A(0) the initial activity
  • A is the activity at time t

We know the activity decrease by a factor of two in a one hour period (t = 1 h), it means that A = \frac{A_{0}}{2}

\frac{A_{0}}{2}=A_{0}e^{-\lambda*1 h}

0.5=e^{-\lambda*1 h}

Taking the natural logarithm on each side we have:

ln(0.5)=-\lambda

\lambda=0.69 h^{-1}

Now, the relationship between the decay constant λ and the half-life t(1/2) is:

\lambda = \frac{ln(2)}{t_{1/2}}

t_{1/2} = \frac{ln(2)}{\lambda}

t_{1/2} = \frac{ln(2)}{0.69}

t_{1/2} = 1.005 h

I hope it helps you!

6 0
3 years ago
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