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daser333 [38]
3 years ago
13

A 60 W bulb is supplied with 36 000 j of energy how long is the bulb on for

Physics
1 answer:
antiseptic1488 [7]3 years ago
8 0

Answer:

Time = 600 seconds

Explanation:

Given the following data;

Power = 60W

Energy = 36000

To find the time;

Energy = power * time

Substituting into the equation, we have;

36000 = 60 * time

Time = 36000/60

Time = 600 seconds.

Therefore, the bulb was on for 600 seconds.

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iVinArrow [24]

Given :

You fire a paintball from a paintball gun straight up into the air at 25.0 m/s.

To Find :

What is the ball velocity at the higher point that the ball reaches.

Solution :

We know, when ball is moving upward acceleration due to gravity is applied downward.

So, the ball will decelerate and when ball reaches maximum height its velocity will become zero.

Therefore, ball velocity is 0 m/s at maximum height.

Hence, this is the required solution.

5 0
3 years ago
The binding energies of K-shell and L-shell electrons in a certain metal are EK and EL, respectively, If a Kαx ray from this met
Svetach [21]

Answer:

The separation distance between the parallel planes of an atom is hc/2sinθ(EK - EL)

Explanation:

The relationship between energy and wavelength is expressed below:

E = hc/λ

λ = hc/EK - EL

Considering the condition of Bragg's law:

2dsinθ = mλ

For the first order Bragg's law of reflection:

2dsinθ = (1)λ

2dsinθ = hc/EK - EL

d = hc/2sinθ(EK - EL)

Where 'd' is the separation distance between the parallel planes of an atom, 'h' is the Planck's constant, 'c' is the velocity of light, θ is the angle of reflection, 'EK' is the energy of the K shell and 'EL' is the energy of the K shell.

Therefore, the separation distance between the parallel planes of an atom is hc/2sinθ(EK - EL)

5 0
3 years ago
When a driver presses the brake pedal, his car can stop with an acceleration of 5.4 m/s2. How far will the car travel while comi
notsponge [240]
Given:\\a=5.4 \frac{m}{s^2}  \\v_0= 25\frac{m}{s} \\\\Find:\\s=?\\\\Solution:\\\\s=v_0t- \frac{at^2}{2} \\\\a= \frac{\Delta v}{t} \\\\v_e=0\Rightarrow \Delta v=v_0\\\\t= \frac{v_0}{a} \\\\s= \frac{v_0^2}{a} - \frac{v_0^2}{2a} =\frac{v_0^2}{2a} \\\\s= \frac{ (25\frac{m}{s})2 }{2\cdot 5.4 \frac{m}{s^2} } \approx 57.9m\\\\C\rightarrow Correct\;answer
3 0
3 years ago
A constant friction force of 21 N acts on a 63-kg skier for 25 s on level snow. What is the skier’s change in velocity?
erica [24]
The skier’s change in velocity is 8.33.../8.4 m/s.
21/63= 0.33...
0.33...x 25 s = 8.33.../8.4 m/s
4 0
3 years ago
More massive objects have a large gravitational force or weight. Why do heavier objects accelerate to the ground at the same rat
8090 [49]

Answer:

D) Heavier objects need a greater force to accelerate according to F=ma.

Explanation:

The force of gravity acting on an object is equal to:

F = mg

where m is the mass of the object and g is the acceleration due to gravity. According to the formula, heavier objects (objects with greater mass, m) have a larger force of gravity acting on them.

However, the acceleration of an object towards the ground is given by:

a=\frac{F}{m}

therefore, we see that if the object is heavier (larger mass, m), the force of gravity (F) must also be larger in order to have the same acceleration a.

5 0
3 years ago
Read 2 more answers
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