1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
navik [9.2K]
3 years ago
12

HOW MANY LICKS DOES IT TAKE TO GET TO THE CENTER OF A TOOTSIE POP?​

Physics
2 answers:
Harman [31]3 years ago
7 0
<h2>Answer:364 LICKS!</h2><h2 />

Explanation:

Alenkinab [10]3 years ago
3 0

Answer:

364 licks

A group of engineering students from Purdue University reported that its licking machine, modeled after a human tongue, took an average of 364 licks to get to the center of a Tootsie Pop.

Explanation:

I spent so much time on this very difficult question for humanity

You might be interested in
Which two statements about an electric motor are true?
allochka39001 [22]

Options (b) and (d) are correct about an electric motor.

An electric motor is a device which coverts electrical energy into mechanical energy.It works on the principle that when a current carrying coil is placed in a magnetic field, it experiences torque. Because of that torque, the coil rotates and thus the electrical energy gets converted into mechanical (motion) energy.

7 0
3 years ago
Read 2 more answers
We experience fictitious forces due to: a. Rotation of a reference frame b. Inertial reference frames c. Translational motion d.
lisabon 2012 [21]

Answer:

A.

Explanation:

A fictional force (also called force of inertia, pseudo-force, or force of d'Alembert, 5), is a force that appears when describing a movement with respect to a non-inertial reference system, and that therefore it does not correspond to a genuine force in the context of the description of the movement that Newton's laws are enunciated for inertial reference systems.

The forces of inertia are, therefore, corrective terms to the real forces, which ensure that the formalism of Newton's laws can be applied unchanged to phenomena described with respect to a non-inertial reference system. The correct answer is A.

8 0
4 years ago
The first step in responding to any sports injury is to __________.
larisa86 [58]

Answer:

THE ANSWER IS..................................................... UHHHH IM JK ITS (A)

Explanation:

6 0
3 years ago
Read 2 more answers
Suppose a small planet is discovered that is 16 times as far from the Sun as the Earth's distance is from the Sun. Use Kepler's
mamaluj [8]

Answer:

23376 days

Explanation:

The problem can be solved using Kepler's third law of planetary motion which states that the square of the period T of a planet round the sun is directly proportional to the cube of its mean distance R from the sun.

T^2\alpha R^3\\T^2=kR^3.......................(1)

where k is a constant.

From equation (1) we can deduce that the ratio of the square of the period of a planet to the cube of its mean distance from the sun is a constant.

\frac{T^2}{R^3}=k.......................(2)

Let the orbital period of the earth be T_e and its mean distance of from the sun be R_e.

Also let the orbital period of the planet be T_p and its mean distance from the sun be R_p.

Equation (2) therefore implies the following;

\frac{T_e^2}{R_e^3}=\frac{T_p^2}{R_p^3}....................(3)

We make the period of the planet T_p the subject of formula as follows;

T_p^2=\frac{T_e^2R_p^3}{R_e^3}\\T_p=\sqrt{\frac{T_e^2R_p^3}{R_e^3}\\}................(4)

But recall that from the problem stated, the mean distance of the planet from the sun is 16 times that of the earth, so therefore

R_p=16R_e...............(5)

Substituting equation (5) into (4), we obtain the following;

T_p=\sqrt{\frac{T_e^2(16R_e)^3}{(R_e^3}\\}\\T_p=\sqrt{\frac{T_e^24096R_e^3}{R_e^3}\\}

R_e^3 cancels out and we are left with the following;

T_p=\sqrt{4096T_e^2}\\T_p=64T_e..............(6)

Recall that the orbital period of the earth is about 365.25 days, hence;

T_p=64*365.25\\T_p=23376days

4 0
3 years ago
An owl weighing 40N is sitting in a tree waiting to dive down to catch a mouse. If the owl's potential energy is 800 J with resp
Natali5045456 [20]

Answer:

<em>h = 20 m</em>

Explanation:

<u>Gravitational Potential Energy</u>

Gravitational potential energy (GPE) is the energy stored in an object due to its vertical position or height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or 9.8 m/s^2.

The weight of an object of mass m is:

W = m.g

Thus, the GPE is:

U=W.h

Solving for h:

\displaystyle h=\frac{U}{W}

The weight of the owl is W=40 N and its GPE is U=800 J.

\displaystyle h=\frac{800}{40}=20

h = 20 m

3 0
3 years ago
Other questions:
  • What is the potential energy of a 2,000-kg car parked at the top of a 30-m hill?
    9·2 answers
  • A wave has a frequency of 58 hz and a speed of 31 m/s. what is the wavelength of this wave?
    15·1 answer
  • The work done in moving an electron through the 3 ohm resistor is
    15·1 answer
  • Two precautions in images of a convex lens
    9·2 answers
  • A spring stretches by 18 cm when a bag of potatoes weighing 56 N is suspended from its end. How much elastic potential energy in
    8·1 answer
  • Chuck and Jackie stand on separate carts, both of which can slide without friction. The combined mass of Chuck and his cart, mca
    7·1 answer
  • Drag the tiles to the correct boxes to complete the pairs.
    5·2 answers
  • An object moving with a constant
    6·2 answers
  • Calculate the kinetic energy of a 8 kg object moving at a velocity of 4 m/s.
    9·2 answers
  • A child looked at
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!