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navik [9.2K]
3 years ago
12

HOW MANY LICKS DOES IT TAKE TO GET TO THE CENTER OF A TOOTSIE POP?​

Physics
2 answers:
Harman [31]3 years ago
7 0
<h2>Answer:364 LICKS!</h2><h2 />

Explanation:

Alenkinab [10]3 years ago
3 0

Answer:

364 licks

A group of engineering students from Purdue University reported that its licking machine, modeled after a human tongue, took an average of 364 licks to get to the center of a Tootsie Pop.

Explanation:

I spent so much time on this very difficult question for humanity

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The speed of sound at room temperature (20 degrees Celsius) is 343 m/s. If the speed of sound in air increases about 0.60 m/s fo
stepan [7]

Answer:

36,67 degrees Celsius

Explanation:

The simplest way to approach this problem, given the information provided, is to simply start with the speed difference.

Goal: 353 m/s

Start: 343 m/s (at 20 degrees Celsius).

Difference: 10 m/s

Variation rate: 0.60 m/s/d (d = degree)

d = \frac{10 m/s}{0.60 m/s/d}  = 16,67 d

So, 16,67 degrees more than the starting point.

The temperature will then be 36.67 degrees Celsius, when the sound travels at the speed of 353 m/s.

4 0
3 years ago
How much kinetic energy does an object have that is moving at a rate of 30 m/s and has a mass of 4000 kg ?
DaniilM [7]

Answer:

K = 1800 kJ

Explanation:

Given that,

The speed of the object, v = 30 m/s

Mass of the object, m = 4000 kg

We need to find the kinetic energy of the object. The formula for the kinetic energy is given by :

K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 4000\times 30^2\\\\K=1800000\\\\or\\\\K=1800\ kJ

So, the required kinetic energy is equal to 1800 kJ.

3 0
2 years ago
ANSWER QUCIK<br> PLS THANK YOU
Reil [10]
Electrical energy in the charger and cable

Chemical energy in the battery of the mobile phone
8 0
3 years ago
A ____ is a non solid state of matter in which the atoms and molecules are free to move past each other, as in a gas or liquid.
Licemer1 [7]
The answer is GAS. In a gas, the particles are in a completely random motion in any direction. And it is not solid. Hope I helped. Good luck
6 0
3 years ago
Read 2 more answers
5.00 kg of liquid water is heated to 100.0 °C in a closed system. At this temperature, the density of liquid water is 958 kg/m3.
user100 [1]

Answer:

1.04\times 10^7\ J.

Explanation:

In the question given :

Pressure is constant

Therefore, Work done, W=P\times\Delta V

Pressure, P=1.01 × 105 Pa.

Final volume, V_f=8.50\ m^3.

Initial volume, V_i=\dfrac{Mass}{density}=\dfrac{5}{958}=5.22\times10^-3\ m^3.

Therefore, W=8.58\times 10^{5}\ J.

Also, Heat Given, Q=m\times L=5\times 2.26\times 10^{6}\ J=1.13\times 10^7\ J.

Also, according to First law of thermodynamics:

\Delta U=Q-W=(1.13\times 10^7)-(8.58\times 10^5)=1.04\times 10^7\ J.

Hence, this is the required solution.

8 0
3 years ago
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