Answer:
The percentage of the weight supported by the front wheel is A= 19.82 %
Explanation:
From the question we are told that
The center of gravity of the plane to its nose is 
The distance of the front wheel of the plane to its nose is 
The distance of the main wheel of the plane to its nose is 
At equilibrium the Torque about the nose of the airplane is mathematically represented as

Where m is the mass of the airplane
is the weight of the airplane supported by the main wheel
So

Substituting values
Now the weight supported at the frontal wheel is mathematically evaluated as

Substituting values
Now the weight of the airplane is = mg
Thus percentage of this weight supported by the front wheel is
19.82 %
Underhand serve is a type of volleyball serve in which a player holds the ball with one hand and swings the other hand in an arc motion, striking under the ball with a fist to put it into play. An underhand serve is the most common serve for beginners.
Answer:
Explanation 118 = (1/2) * 0.15 * v² 118 = 0.075 * v² v² = 1573.33 m/s ... since KE = m/2*V^2 , then : V = √2KE/m = √20*118/1.5 = 39.67 m//sec ( 142.8 km/h ; 88.75 mph).: