This looks complicated, but it's actually not too tough.
The formula for the gravitational force between two objects is
Force = G (one mass) (other mass) / (distance²) .
The question GAVE us all of those numbers except the distance.
All we have to do is pluggum in, massage it around, and find
the distance.
Force = 4.18 x 10¹⁵ N
G = 6.673 x 10⁻¹¹ N·m²/kg²
One mass = 6.58 x 10²³ kg
Other mass = 9.3 x 10¹⁵ kg .
The only tricky thing about this is gonna be the arithmetic ...
keeping all the exponents straight.
Take the formula for the gravitational force and plug in
everything we know:
Force = (G) · (one mass) · (other mass) / (distance²)
4.18x10¹⁵N = (6.673x10⁻¹¹N-m²/kg²)·(6.58x10²³kg)·(9.3x10¹⁵kg) / (distance²).
Multiply each side by (distance²):
(distance²)·(4.18x10¹⁵N) = (6.673x10⁻¹¹N-m²/kg²)·(6.58x10²³kg)·(9.3x10¹⁵kg)
Divide each side by (4.18 x 10¹⁵ N) :
(distance²)=(6.673x10⁻¹¹N-m²/kg²)·(6.58x10²³kg)·(9.3x10¹⁵kg) / (4.18x10¹⁵N)
That's the end of the Physics and Algebra. The only thing left is Arithmetic.
We have to simplify that whole ugly thing on the right side of the equation,
and then take the square root of each side.
When I crunch down the right side of that equation, I get
(distance²) = 9.769 x 10¹³ m²
and when I take the square root of each side, I get
distance = 9.884 x 10⁶ meters . **
You should check my Arithmetic. **
(Pause occasionally to let your calculator cool off.)
BY THE WAY ...
That "distance" in the equation for gravitational force is the distance
between the CENTERS of the two objects.
This doesn't make much difference for Phobos, because Phobos isn't
much bigger than a big sweet potato. But it does make a difference for
Mars.
The 'distance' we find with all of this nonsense is NOT the distance
between Phobos and the surface of Mars. It's the distance between
Phobos and the CENTER of Mars, so it includes the planet's radius.
** Consulting online resources between Floogle and Flickerpedia,
I found that the orbital distance of Phobos from Mars varies between
9,234 km and 9,517 km. Add the planet's radius to these, and I'm
beginning to feel confidence in the results of my back-of-the-napkin
calculation. But you should still check my Arithmetic.
Answer:
The environmental protection agency needs to inspect the ship and make sure it is safe before giving the ok.
Explanation:
this agency is doing its job due to they have to be sure that this ship will be sure for the marine life.
<h2>
Answer: 10615 nm</h2>
Explanation:
This problem can be solved by the Wien's displacement law, which relates the wavelength
where the intensity of the radiation is maximum (also called peak wavelength) with the temperature
of the black body.
In other words:
<em>There is an inverse relationship between the wavelength at which the emission peak of a blackbody occurs and its temperature.</em>
Being this expresed as:
(1)
Where:
is in Kelvin (K)
is the <u>wavelength of the emission peak</u> in meters (m).
is the <u>Wien constant</u>, whose value is 
From this we can deduce that the higher the black body temperature, the shorter the maximum wavelength of emission will be.
Now, let's apply equation (1), finding
:
(2)
Finally:
This is the peak wavelength for radiation from ice at 273 K, and corresponds to the<u> infrared.</u>
Answer:
3 and 2
May be
ok may be subscribeIsenberg Isenberg Ignatius
Answer: 42.49
Explanation:
To solve this, we need to keep in mind the following:
While the sphere hangs it is under the effect of gravity. It is creating a Angle of 90° taking the roof as a reference.
Gravity can be noted as a Acceleration Vector. The magnitud for Earth's Gravity is a constant: 9.81 
The acceleration of the Van will affect the sphere also, but this accelaration will be on the X-axis and perpendicular to the gravity. Because this two vectors are taking action under the sphere they will create a angle. This angle can be measured as a relation of the two magnitudes.
Tangent (∅) = Opossite Side / Adyacent Side
By trigonometry, we know the previous formula. This formula allows us to find the Tangent of a angle as a relation between the two perpendiculars magnitudes. In this case the Opossite Side will be the Gravity Accelaration, while the Adyancent Side is the Van's Acceleration.
(1) Tangent (∅) = Gravity's Acceleration (G) / Van's Acceleration (Va)
Searching for the Va in (1)
Va = G/Tan(∅)
Where ∅ in this case is equal to 13.0°
Va = 9.81
/ Tan(13.0°)
Va = 42.49
The vans acceleration need to be 42.49
to create an angle of 13° with the Van's Roof