Let the four consecutive integers be
x , x+1, x+2, x+3
ATQ, Their sum is 18
<h3>Now,</h3>
- 1st number = x = 3
- 2nd number = x+1 = 3+1 = 4
- 3rd number = x+2 = 3+2 = 5
- 4th number = x+3 = 3+3 = 6
<em>The four numbers are 3,4,5,6 respectively and the smallest number among them is 3</em><em>.</em><em>.</em><em>.</em><em>~</em>
Answer:
" > "
Step-by-step explanation:
-4/5=4x9 5×9
-4/5 = - 36/ 45
-8/9=8×5 9×5
-8/9 =-40/45
-36/ 45 > -40/45
-4/5 > -8/9
in this case - 4/5 is closer to 0
Answer: 6.1 > 1.6 (greater)
Step-by-step explanation:
6 in 6.1 is greater than the 1 in 1.6
Assume uniformly accelerated motion
Vf = Vo - at => a= [Vo - Vf] / t
Vf = 0, t = 20 s => a = Vo / 20
x = Vot - at^2 / 2
x = Vot - (Vo / 20) * t^2 /2
x = 1775 feet * [1 mile / 5280 feet] = 0.336 mile
t = 20 s
=> 0.336 = 20Vo - Vo(20)^2 /(40) = 20Vo - 10 Vo = 10 Vo
=> Vo = 0.336 /10 = 0.0336 mile /s
Vo = 0.0336 mile/s * 3600 s/h = 120.96 mile / h
Therefore, the car was way over the speed limit.
