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pishuonlain [190]
4 years ago
7

An individual who has automobile insurance from a certain company is randomly selected. What is the probability that among 15 ra

ndomly chosen such individuals, at least 10 have no citations?

Mathematics
1 answer:
olchik [2.2K]4 years ago
6 0

Answer: B( 5 : 15,0)

Step-by-step explanation: Please find the attached file for the solution

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6.4 ÷ 0.043<br><br> Round your answer to the nearest whole number.
lys-0071 [83]

Answer:

149

Step-by-step explanation:

6.4 ÷ 0.043

= 148.837209302

= 149 (rounded to the nearest whole number)

Hope this helped!

6 0
3 years ago
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In the equation x=−3y, what is the unit rate?
Paul [167]
The unit rate is -1/3.

In direct variation, y varies directly to x by a constant ratio k.

Its equation looks like this: y = kx ; where k stands for the constant ratio.

In the above equation. x = -3y, it should be converted to the proper equation. both sides must be transferred and its accompanying sign must be changed.

3y = -x
3y/3 = -x/3
y = (-1/3)x
where: y is the total value; -1/3 is the unit rate; and x is the number of units


 
6 0
3 years ago
What is .363636 as a fraction
Kay [80]
.363636 as a fraction is 4/11
6 0
4 years ago
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A 1.5-mm layer of paint is applied to one side of the following surface. Find the approximate volume of paint needed. Assume tha
Mariulka [41]

Answer:

V = 63π / 200  m^3

Step-by-step explanation:

Given:

- The function y = f(x) is revolved around the x-axis over the interval [1,6] to form a spherical surface:

                                 y = √(42*x - x^2)

- The surface is coated with paint with uniform layer thickness t = 1.5 mm

Find:

The volume of paint needed

Solution:

- Let f be a non-negative function with a continuous first derivative on the interval [1,6]. The Area of surface generated when y = f(x) is revolved around x-axis over the interval [1,6] is:

                           S = 2*\pi \int\limits^a_b { [f(x)*\sqrt{1 + f'(x)^2} }] \, dx

- The derivative of the function f'(x) is as follows:

                            f'(x) = \frac{21-x}{\sqrt{42x-x^2} }

- The square of derivative of f(x) is:

                            f'(x)^2 = \frac{(21-x)^2}{42x-x^2 }

- Now use the surface area formula:

                           S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2} *\sqrt{1 + \frac{(21-x)^2}{42x-x^2 } }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2+(21-x)^2} }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2+441-42x+x^2} }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{441} }] \, dx\\S = 2*\pi \int\limits^6_1 { 21} \, dx\\\\S = 42*\pi \int\limits^6_1 { dx} \,\\\\S = 42*\pi [ 6 - 1 ]\\\\S = 42*5*\pi \\\\S = 210\pi

- The Volume of the pain coating is:

                           V = S*t

                           V = 210*π*3/2000

                          V = 63π / 200 m^3

8 0
4 years ago
Read 2 more answers
Please help me with this math
Lynna [10]
Number 3: 176 squared cm
7 0
3 years ago
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