Inflection point is the point where the second derivative of a graph is zero.
y = (x+1)arctan xy' = (x+1)(arctan x)' + (1)arctan xy' = (x+1)/(x^2+1) + arctan xy'' = (x+1)(1/(1+x^2))' + 1/(1+x^2) + 1/(1+x^2)y'' = (x+1)(-1/(1+x^2)^2)(2x)+2/(1+x^2)y'' = ((x+1)(-2x)+1+x^2)/(1+x^2)^2y'' = (-2x^2-2x+2+2x^2)/(1+x^2)^2y'' = (-2x+2)/(1+x^2)^2
Solving for point of inflection: y'' = 00 = (-2x+2)/(1+x^2)^20 = -2x+2x = 1y(1) = (1+1)arctan(1) = 2 * pi/4 = pi/2
Therefore, E(1, pi/2).
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Answer:
x^2+14x+49 ( it could be polynomial because it has 3 terms and each term has a whole number and a coefficient)
Step-by-step explanation:
(x+7)^2
(x+7)(x+7)
x^2+7x+7x+49
x^2+14x+49
I am not sure it's a polynomial or not
Answer:
s = 
Step-by-step explanation:
s = ut + 
at² ( substitute the given values into the equation )
s = ( 3 × ) + ( × - 12 × ( )² )
= 1 + (- 6 × 
)
= 1 + ( - 
)
= 1 -
=
1st Question:
X = 18
2nd Question:
X=20
