The volume of CO₂ at STP = 2.8 L
<h3>Further explanation</h3>
Given
21 gram of sodium hydrogen carbonate-NaHCO₃
Required
Volume of CO₂
Solution
The decomposition of sodium bicarbonate into sodium carbonate, carbon dioxide, and water :
<em>
2 NaHCO₃(s) → Na₂CO₃(s) + CO₂(g) + H₂O(g)</em>
mol of NaHCO₃ :
= mass : MW NaHCO₃
= 21 g : 84 g/mol
= 0.25
From the equation, mol ratio of NaHCO₃(s) :CO₂(g) = 2 : 1, so mol CO₂ :
= 1/2 x mol NaHCO₃
= 1/2 x 0.25
= 0.125
At STP, 1 mol gas = 22.4 L, so for 0.125 mol :
= 0.125 x 22.4 L
= 2.8 L
Density = Mass / Volume
10.5 = 500 / x
10.5x = 500
x = 50 cm^3 (1 sig fig) volume of the sphere
Volume of a sphere = 4/3 pi r^2
pi = 3.14 r = radius
50 = 4/3 pi r^3
50•3/4 = pi r^3
37.5 = pi r^3
37.5/pi = r^3
11.9 = r^3
cube root(11.9) = r
2.3 = r
Diameter = 2•radius
Diameter = 2 • 2.3
Diameter = 5 cm (1 sig fig) diameter
Answer:
That they are miscible in one another
Answer: okay, girl I got you . Chemical.
Nuclear.
Thermal.
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Explanation: hope this helped and please mark me brainiest.
Answer:
A
Explanation:
i did it before and got it right
