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dexar [7]
3 years ago
14

Which of the following factors affect the vapor pressure of a liquid? Check all that apply. View Available Hint(s) Check all tha

t apply. atmospheric pressure surface area of the liquid temperature amount of liquid type of liquid addition of solute
Chemistry
1 answer:
trasher [3.6K]3 years ago
6 0

Answer:

Vapour pressure of liquid is affected by its TEMPERATURE, TYPE OF LIQUID, ADDITION OF SOLUTES.

Explanation:

Vapor pressure is the pressure exerted by a vapor in equilibrium with its liquid. Mathematically, the vapor pressure of liquid is written as:

In (Pvap) = -ΔHvap / R * (1/T) + C

ΔHvap is the enthalpy of vaporization and it is constant for specific liquid, T is the temperature and C is a constant. Temperature therefore affect the vapor pressure of a liquid as increase in temperature can cause an increase in vapor pressure.

The type of liquid also affect the vapor pressure. If the molecules bind to each other strongly in the liquid, it increases vapor pressure to be exerted by the liquid but if the type of liquid is one with weak forces of attraction, the vapor pressure is reduced.

Addition of solute to the liquid increases the boiling temperature of liquids thereby reducing it's vapor pressure.

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What is the ultimate end of a high mass star that has a core about 2.8x the mass of our sun?
jolli1 [7]

Answer:

A

Explanation:

It is formed after the star has ended its star cycle into a supernova. The star collapsed into a neutron star that is smaller than the progenitor star but has inherited angular momentum. IT, therefore, spins faster emitting electromagnetic radiation that seems to pulsate.

5 0
3 years ago
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The combustion of palmitic acid is represented by the chemical equation: C16H32O2(s) + 23O2(g) → 16 CO2(g) + 16 H2O(l) The magni
solniwko [45]

Answer:

The correct option is C

Explanation:

From the question we are told that

The reaction is

C_{16}H_{32}O_2(g) + 23O_2(g) \to 16 CO_2(g) + 16 H_2O(l)

Generally \Delta  H  =  \Delta  U + \Delta N*  RT

Here \Delta  H is the change in enthalpy

\Delta  U is the change in the internal energy

              \Delta N  is the difference between that number of moles of product and the number of moles of reactant

Looking at the reaction we can discover that the elements that was consumed and the element that was formed is O_2 and  CO_2 and this are both gases so the change would occur in the number of moles

So  

\Delta  H  =  \Delta  U + [16 -23]*  RT

\Delta  H  =  \Delta  U -7RT

The  negative sign in the equation tell us that the enthalpy\Delta_r H would be less than the Internal energy \Delta_r U

4 0
3 years ago
When water freezes into ice, sme of the properties have changed <br> What stays the same
larisa86 [58]
When water freezes into ice, some of the properties have change. What stays the same.




Answer: 1: Ice Melting is a physical change. When liquid water (H2O) freezes into a solid state (ice), it appears changed; However, this change is only physical as the the composition of the constituent molecules is the same: 11.19% hydrogen and 88.81% oxygen by mass.


Have a goood day!
5 0
3 years ago
A sample of O2 with an initial temperature of 50.0 oC and a volume of 105 L is cooled to -25 oC. The new pressure is 105.4 kPa a
Damm [24]

Answer:

71.92 kPa

Explanation:

Using the combined gas law equation;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (kPa)

P2 = final pressure (kPa)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

T1 = 50°C = 50 + 273 = 323K

V1 = 105L

T2 = -25°C = -25 + 273 = 248K

P2 = 105.4 kPa

P1 = ?

V2 = 55.0 L

Using P1V1/T1 = P2V2/T2

P1 × 105/323 = 105.4 × 55/248

105P1/323 = 5797/248

0.325P1 = 23.375

P1 = 23.375 ÷ 0.325

P1 = 71.92 kPa

4 0
3 years ago
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