Explanation:
P1V1 = P2V2
(100.7 kPa)(0.75 L) = (99.8 kPa)V2
V2 = (100.7 kPa)(0.75 L)/(99.8 kPa)
= 0.757 L
Answer:
This flexible ability is important because it allows the cell to survive in differing environments, such as when immersed in water over long periods of time.
Answer:
0.727 l.
Explanation:
For the new dilute Sulphuric acid,
Number of moles = molar concentration × volume
= 2.5 × 5
= 12.5 mol
Volume of concentrated solution = 12.5/17.2
= 0.727 l of 17.2 M of sulphuric acid to be diluted.
To convert 78.1 g of water at 0° C to Ice at -57.1°C; we can do it in steps;
1. Water at 0°C to ice at 0°C
The heat of fusion of ice is 334 J/g;
Heat = 78.1 × 334 = 26085.4 Joules
2. Ice at 0°C to -57.1°C
Specific heat of ice is 2.108 J/g
Heat = 78.1 × 2.108 J/g = 164.6348 Joules
Thus the total heat energy released will be; 26085.4 + 164.6348
= 26250.0348 J or 26.250 kJ
