10. Blood which is flung off of swinging objects creates which type of spatter?

Ludmilka [50]

Im not really sure but my best guess is d 52.8%

7 0

2 years ago

A 25.0 ml solution of .0600 M EDTA was added to a 57.0 ml sample containing an unknown concentration of V3+. All V3+ present for

Rom4ik [11]

Explanation:

Let us assume that the ratio for the given reaction is 1:1.

Therefore, we will calculate the moles of $Ga^{3+}$ as follows.

Moles of $Ga^{3+}$ solution = molarity × volume (L)

= 0.0440 M × 0.014 L

= 0.000616 moles

Moles of excess EDTA = 0.000616 moles

Also, the initial moles of EDTA will be calculated as follows.

Total initial moles of EDTA = 0.0600 M × 0.025 L

= 0.0015

Therefore, moles of EDTA reacted with $V^{3+}$ will be as follows.

= 0.0015 - 0.000616

= 0.00088 moles

Since, we have supposed a 1 : 1 ratio between $V^{3+}$ and EDTA .

So, moles of $V^{3+}$ = 0.00088 moles

Now, we will calculate the molarity of $V^{3+}$ as follows.

Molarity of $V^{3+}$ solution = $\frac{\text{moles}}{\text{volume (L)}}$

= $\frac{0.00088 moles}{0.057 L}$

= 0.015 M

Thus, we can conclude that the original concentration of the $V^{3+}$ solution is 0.015 M.

4 0

3 years ago

How to find the value of the equilibrium

adell [148]

Calculating K from Known Initial Amounts and the Known Change in Amount of One of the SpeciesWrite the equilibrium expression for the reaction.Determine the molar concentrations or partial pressures of each species involved.Determine all equilibrium concentrations or partial pressures using an ICE chart.

6 0

4 years ago

A student was asked to determine the concentration of ammonia, a volatile substance used in the clinical setting as a respiretor

UNO [17]

This question is describing two chemical equations whereby the concentration of ammonia has to be determined. The first reaction is between 25.00 mL of ammonia and 50.00 mL of 0.100-M HCl whose excess was neutralized with 21.50 mL of 0.050-M Na₂CO₃ and thus, the concentration ammonia in the cloudy solution was determined as 0.114 M.

First of all we need to go over the titration of the excess HCl with Na₂CO₃ by writing the chemical equation it takes place when they react:

$2HCl+Na_2CO_3\rightarrow 2NaCl+CO_2+H_2O$

Whereas the mole ratio of HCl to Na₂CO₃ is 2:1 and the volume of the HCl leftover is determined as follows:

$V_{HCl}^{leftover}=\frac{2*0.050M*21.50mL}{0.100M} =21.5mL$

Next, we infer that the consumed volume of HCl by the ammonia solution was:

$V_{HCl}^{consumed}=50.00mL-21.50mL=28.5 mL$

Then, we write the chemical equation that takes place between ammonia and HCl:

$HCl+NH_3\rightarrow NH_4Cl$

Whereas the mole ratio is now 1:1, which means that the concentration of ammonia was:

$M_{NH_3}=\frac{28.5mL*0.100M}{25.00mL}\\\\ M_{NH_3}=0.114M$

Learn more:

(Titration) brainly.com/question/15687419
(Titration) brainly.com/question/25328286

8 0

2 years ago

What is he difference between ligaments and tendons

inn [45]

Tendons may also attach muscles to structures such as the eyeball. A tendon serves to move the bone or structure. A ligament is a fibrous connective tissue which attaches bone to bone, and usually serves to hold structures together and keep them stable.

7 0

3 years ago

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