Answer:
at P = 101 KPa ⇒ S = 2.1 g/L
Explanation:
Henry's law:
∴ K: Henry's constant
∴ <em>C</em> is the concentration ≡ Solubiluty (S)
∴ S = (8.4 g/L)*(Kg/1000 g)*(1000 L/m³) = 8.4 Kg/m³
∴ P = (404 KPa)*(1000 Pa/KPa) = 404000 Pa
∴ Pa = Kg/ms²
⇒ S = K(404000 Pa) = 8.4 Kg/m³
⇒ K = 2.079 E-5 s²/m².......the henry's constant for this gas
at P = 101 KPa = 101000 Pa
⇒ S = (2.079 E-5 s²/m²)*(101000 Kg/ms²)
⇒ S = 2.1 Kg/m³ = 2.1 g/L
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