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2 years ago

Which of the following describes the properties of a base?

1 answer:

6 0

I would say B, because in normal reactions (non-nuclear) protons are not moved around, and according to Bronsted-Lowry theory, bases accept ELECTRONS. Thus the answer cannot be A, C, or D and must be B.

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6. What is the total number of calories lost when 10

Nadusha1986 [10]

Answer:

Explanation:

so you started out with 80

you have to cool it till 60

so it is decreasing which means you have to subtract

Note=if something is increasing or wanting to go up its addition but for this problem 60 is less then 80 so we are doing subtraction

80-60=20

3 0

2 years ago

Rxn

givi [52]

Answer: The enthalpy of formation of $SO_3$ is -396 kJ/mol

Explanation:

Calculating the enthalpy of formation of $SO_3$

The chemical equation for the combustion of propane follows:

$2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H^o_{rxn}=[(2\times \Delta H^o_f_{(SO_3(g))})]-[(2\times \Delta H^o_f_{(SO_2(g))})+(1\times \Delta H^o_f_{(O_2(g))})]$

We are given:

$\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(SO_2(g))}=-297kJ/mol\\\Delta H^o_{rxn}=-198kJ$

Putting values in above equation, we get:

$-198=[(2\times \Delta H^o_f_{(SO_3(g))})]-[(2\times \Delta -297)+(1\times (0))]\\\\\Delta H^o_f_{(SO_3(g))}=-396kJ/mol$

The enthalpy of formation of $SO_3$ is -396 kJ/mol

4 0

3 years ago

Write some sentences about Respiration in your own words

weeeeeb [17]

Answer:

Reluctantly she pulled away, her pulse and respiration in a race.

Its function is less that of respiration than of FIG

Terrestrial plants have a gaseous interchange of oxygen and carbon dioxide which is necessary for respiration and feeding.

The least wind raises clouds of fine dust, which fill the air, render it so opaque as to obscure the noonday sun, and make respiration difficult.

6 0

1 year ago

The smallest particle of a covalently bonded compound is a(n) ________.

vazorg [7]

The smallest particle of a covalently bonded compound is an atom.

8 0

3 years ago

Read 2 more answers

1. Magnesium chloride solution reacts with silver nitrate solution to form magnesium nitrate

Whitepunk [10]

a. 1,4332 g

b. 7.54~g

<h3>Further explanation</h3>

Given

Reaction

MgCl2 (s) + 2 AgNO3 (aq) → Mg(NO3)2 (aq) + 2 AgCl (s)

20 cm of 2.5 mol/dm^3 of MgCl2

20 cm of 2.5 g/dm^3 of MgCl2

Required

the mass of silver chloride - AgCl

Solution

a. mol MgCl2 :

$\tt 20~cm^3=20\times 10^{-3}~dm^3\\\\mol=M\times V\\\\mol=2.5~mol/dm^3\times 20\times 10^{-3}DM^3=0.05$

From equation, mol AgCl = 2 x mol MgCl2=2 x 0.05=0.1

mass AgCl(MW=143,32 g/mol)= 0.1 x 143,32=1,4332 g

b. mol MgCl2 (MW=95.211 /mol):

$\tt mol=M\times V\\\\mol=\dfrac{2.5~g/dm^3}{95,211 g/mol}=0.0263~mol/dm^3$

From equation, mol AgCl = 2 x mol MgCl2=2 x 0.0263=0.0526

mass AgCl(MW=143,32 g/mol)= 0.0526 x 143,32=7.54~g

6 0

2 years ago