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ss7ja [257]
3 years ago
10

The compound borazine consists of 40.29% boron, 7.51%

Chemistry
1 answer:
ioda3 years ago
7 0

Answer:

B_3H_6N_3

Explanation:

Hello there!

In this case, since the mass percentages in a compound which is wanted to know the molecular formula, can be assumed to be the masses, we first need to compute the moles they have in the formula unit:

n_B=40.29gB*\frac{1molB}{10.811gB} =3.73molB\\\\n_H=7.51gH*\frac{1molH}{1.01gH} =7.44molH\\\\n_N=52.20gN*\frac{1molN}{14.01gN} =3.73molN

Next, we divide each moles by the fewest ones (3.73 mol) in order to find the subscript in the empirical formula first:

B:\frac{3.73}{3.73}=1 \\\\H:\frac{7.44}{3.73}=2\\\\N:\frac{3.73}{3.73}=1

Then, the empirical formula is BH2N whose molar mass is 26.83 g/mol, so the ratio of molecular to empirical is 80.50/26.83=3; therefore, the molecular formula is three times the empirical one:

B_3H_6N_3

Best regards!

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weqwewe [10]

Explanation:

Find the motion diagram attached for the illustration:

Distance is the length of path traveled from the start to the finish. In measuring distance, we wall through the path from start to the finishing point. Distance is a scalar magnitude that has magnitude but no direction.

Displacement is distance that is taken between the start and finishing point. It is a vector quantity that has magnitude and measures direction.

To find the distance;

Distance = 5km + 7km = 12km

Displacement:

 Using pythagoras theorem;

   Displacement = √7² + 5² = 8.6km

 Direction:

    sin(bearing ) = \frac{5}{8.6}  = 0.5814

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learn more:

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6 0
2 years ago
The temperature of a sample of gas in steel container at 30.3 Atm is
vladimir1956 [14]

Answer:

74.09 atm

Explanation:

Using the gas laws ( Charles and Boyle's law). We have the formula ,

P1/T1 = P2/T2

Where P1 = 30.3atm

T1 = -100 degree Celsius

to kelvin = -100+ 273 = 173K

T2 = 150 degree Celsius

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Imputing values

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30.3/173 = P2/ 423

Cross multiply

173×P2 = 30.3 ×423

173P2 = 12816.9

Divide both sides by 173

P2 = 12816.9/173

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I hope this was helpful, please mark as brainliest

6 0
3 years ago
Read 2 more answers
How many moles of sodium bicarbonate are in 1.50 kg of the compound?
salantis [7]

Answer:

n=17.85 moles

Explanation:

Given mass is, m = 1.5 kg = 1500 g

The molar mass of sodium bicarbonate is, M = 84.007 g/mol

We need to find the no of moles in 1.5 kg of Sodium bicarbonate . We know that, no of moles is equal to given mass divided by molar mass.

n=\dfrac{m}{M}\\\\n=\dfrac{1500}{84.007 }\\\\n=17.85

<h2>So, there are 17.85 moles in 1.5 kg of Sodium bicarbonate.</h2>
3 0
3 years ago
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Ratling [72]

Answer:

Entropy.

Explanation:

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4 0
2 years ago
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