Explanation:
Find the motion diagram attached for the illustration:
Distance is the length of path traveled from the start to the finish. In measuring distance, we wall through the path from start to the finishing point. Distance is a scalar magnitude that has magnitude but no direction.
Displacement is distance that is taken between the start and finishing point. It is a vector quantity that has magnitude and measures direction.
To find the distance;
Distance = 5km + 7km = 12km
Displacement:
Using pythagoras theorem;
Displacement = √7² + 5² = 8.6km
Direction:
sin(bearing ) = 
bearing = arcSin 0.5814 = 035.6°
Displacement is 8.6km in a direction 035.6°
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Answer:
74.09 atm
Explanation:
Using the gas laws ( Charles and Boyle's law). We have the formula ,
P1/T1 = P2/T2
Where P1 = 30.3atm
T1 = -100 degree Celsius
to kelvin = -100+ 273 = 173K
T2 = 150 degree Celsius
To Kelvin = 150 = 150+273 = 423K
Imputing values
P1/T1 = P2/T2
30.3/173 = P2/ 423
Cross multiply
173×P2 = 30.3 ×423
173P2 = 12816.9
Divide both sides by 173
P2 = 12816.9/173
P2 = 74.09 atm
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Answer:
n=17.85 moles
Explanation:
Given mass is, m = 1.5 kg = 1500 g
The molar mass of sodium bicarbonate is, M = 84.007 g/mol
We need to find the no of moles in 1.5 kg of Sodium bicarbonate . We know that, no of moles is equal to given mass divided by molar mass.

<h2>
So, there are 17.85 moles in 1.5 kg of Sodium bicarbonate.</h2>
Answer:
Entropy.
Explanation:
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A peptide bond contains <span>amide bonds.
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