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3 years ago

The melting of polar ice is one effect of

1 answer:

5 0

The melting of polar ice is one effect of the greenhouse effect, or also global warming.

The greenhouse effect, as defined by Merriam-Webster, is "the <span>warming of the surface and lower atmosphere of a planet (as Earth or Venus) that is caused by conversion of solar radiation into heat in a process involving selective transmission of short wave solar radiation by the atmosphere, its absorption by the planet's surface, and reradiation as infrared which is absorbed and partly reradiated back to the surface by atmospheric gases".

In short, "</span>the warming of the surface and lower atmosphere of a planet".

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If a conducting loop of radius 10 cm is onboard an instrument on Jupiter at 45 degree latitude, and is rotating with a frequency

Pepsi [2]

Answer:

a) fem = - 2.1514 10⁻⁴ V, b) I = - 64.0 10⁻³ A, c) P = 1.38 10⁻⁶ W

Explanation:

This exercise is about Faraday's law

fem = $- \frac{ d \Phi_B}{dt}$

where the magnetic flux is

Ф = B x A

the bold are vectors

A = π r²

we assume that the angle between the magnetic field and the normal to the area is zero

fem = - B π 2r dr/dt = - 2π B r v

linear and angular velocity are related

v = w r

w = 2π f

v = 2π f r

we substitute

fem = - 2π B r (2π f r)

fem = -4π² B f r²

For the magnetic field of Jupiter we use the equatorial field B = 428 10⁻⁶T

we reduce the magnitudes to the SI system

f = 2 rev / s (2π rad / 1 rev) = 4π Hz

we calculate

fem = - 4π² 428 10⁻⁶ 4π 0.10²

fem = - 16π³ 428 10⁻⁶ 0.010

fem = - 2.1514 10⁻⁴ V

for the current let's use Ohm's law

V = I R

I = V / R

I = -2.1514 10⁻⁴ / 0.00336

I = - 64.0 10⁻³ A

Electric power is

P = V I

P = 2.1514 10⁻⁴ 64.0 10⁻³

P = 1.38 10⁻⁶ W

6 0

3 years ago

A small sphere has a harge of 9uC and other small sphere has a charge of 4uC.

Helga [31]

Answer:

Electrical force, F = 90 N

Explanation:

It is given that,

Charge on sphere 1, $q_1=9\ \mu C=9\times 10^{-6}\ C$

Charge on sphere 2, $q_1=4\ \mu C=4\times 10^{-6}\ C$

Distance between two spheres, d = 6 cm = 0.06 m

Let F is the electrical force between them. It is given by the formula of electric force which is directly proportional to the product of charges and inversely proportional to the square of distance between them such that,

$F=k\dfrac{q_1q_2}{d^2}$