Answer:
Incomplete question: "Each block has a mass of 0.2 kg"
The speed of the two-block system's center of mass just before the blocks collide is 2.9489 m/s
Explanation:
Given data:
θ = angle of the surface = 37°
m = mass of each block = 0.2 kg
v = speed = 0.35 m/s
t = time to collision = 0.5 s
Question: What is the speed of the two-block system's center of mass just before the blocks collide, vf = ?
Change in momentum:




It is neccesary calculate the force:

Here, g = gravity = 9.8 m/s²


Answer:
P = 180.81 J
Explanation:
Given that,
Mass of a object, m = 4.1 kg
It is lifted to a height of 4.5 m
We need to find the potential energy of the object due to gravity. It is given by the formula as follows :
P = mgh Where g is acceleration due to gravity
P = 4.1 kg × 9.8 m/s² × 4.5 m
P = 180.81 J
Hence, the potential energy is 180.81 J.
Answer:
3Q / 4 pi (R^3 - r^3)
Explanation:
Charge density = charge / volume
volume of a spherical shell = 
W=mg
a. W=0.01*9.81=0.0981N
b. W=3.6*9.81=35.316N
c.W=0.713*9.81=6.99453N