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kipiarov [429]
3 years ago
5

A constant force is applied to an object, causing the object to accelerate at 10 m/s^2. What will the acceleration be if: a) The

force is halved? b) The object's mass is halved? c) The force and the object's mass are both halved?
Physics
1 answer:
Liula [17]3 years ago
5 0
What you need to know is that the force is

F=ma

The force is the product of mass and acceleration

this means that the acceleration is

a=F/m

a) The force is halved?
this means that f will be \frac{F}{2} now:

a=\frac{F}{2m}

So the accelaration will also he halved (it's the original acceleratation divided by 2)


 b) The object's mass is halved?
a=\frac{F}{m/2}=a=\frac{F2}{m}

which is the original acceleration times two!! so it will double


c) The force and the object's mass are both halved?
now we have

a=\frac{F/2}{m/2}=a=\frac{2F}{2m}=a=\frac{F}{m}

so they will cancel each other out and the acceleration will stay the same!











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Explanation:

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While the magnitude of the force of gravity is constant, the magnitude of the air resistance increases as the velocity of the falling object increases: at some point of the motion, the air resistance becomes equal in magnitude to the force of gravity. At this point, the net force on the object becomes zero, and according to Newton's second law, the acceleration of the object becomes also zero:

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But zero acceleration means that the velocity of the object is now constant: this is known as terminal velocity.

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A negative charge feels a force when stationary in an electric field. moving parallel to an electric field. moving parallel to a
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<u>stationary in an electric field. </u>

<u>moving perpendicular to a magnetic field.</u>

<u>moving perpendicular to an electric</u> <u>field.</u>

Explanation:

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However, the correct answer in the question above, would be:

<u>"stationary in an electric field". </u>

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A block of mass 1.3 kg is resting at the base of a frictionless ramp. A bullet of mass 50 g is traveling parallel to the ramp su
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Answer:

s = 2.65 m

Explanation:

given,

mass of block,M = 1.3 Kg

mass of bullet,m = 50 g = 0.05 Kg

speed of bullet,u  = 250 m/s

speed of bullet after collision,v = 100 m/s

distance traveled by the block = ?

Assuming the angle of inclination of ramp equal to 40°

calculating the speed of the block

using conservation of momentum

M u' + m u = m v + M v'

initial speed of the block is equal to zero

0 + 0.05 Kg x 250 = 0.05 x 100 + 1.3 x v'

1.3 v' = 7.5

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now, calculation of acceleration

equation  the horizontal component

-mg sin θ = ma

  a = - g sin θ

  a = - 9.8 x sin 40°  

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using equation of motion for the calculation of distance moved by the block

v² = u² + 2 a s

0² = 5.77² + 2 x (-6.29) x s

12.58 s = 33.29

s = 2.65 m

hence, the distance moved by the block is equal to 2.65 m

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A. It is the only one that makes sense

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