Parent #1 has the alleles of IA and i
Parent #2 has the alleles of IB and i
A punnet squares is a simple diagram that illustrates the possible genotypes of the offspring of these two people.
Parent #1 is across the top and Parent #2 is along the side
IA i
IB AB IBi
i IAi ii
For IA or IB will be dominant to i. So for phenotype purposes their offspring have a 25% chande of being AB, 25% chance of B, 25% chance of A and a 25% change of type O (ii)
This Is called deforestacion if to many trees are cut animals either have to adapt or find a new place if this doesnt happen the die
Answer:
<h2>D) 610:190, round seeds:wrinkled seeds</h2>
Explanation:
Let round seed as R and wrinkled seed as r.
So the round is dominant (R) over wrinkled(r).
Hence , round is dominant and wrinkled is recessive rr.
Now cross between pure round (RR) and pure wrinkled (rr).
RR× rr
F1 offspring are: Rr ( all)
Now cross between F1 offspring;
Rr × Rr
F2 are= RR, Rr, Rr and rr
RR and Rr = round
rr= wrinkled.
round to wrinkle ratio is= 3:1
So, 610:190; round seeds:wrinkled seeds is the expected result in the F2 progeny.
Answer:
perhaps
Explanation:
it is dependant of our munition supplies A
Answer:
You inherited a normal amount of genetic material from your mother but inherited an extra chromosome from your father.
Explanation:
It seems logical because if you think about it. If one of your father's gametes were made incorectly and you got it you could come out looking deformed or you can have something extra.
Please let me know if I'm wrong.
