Answer:
1 oz = 29.574 ml
16 oz = About 480 ml, so, yes, the answer is C.
Explanation:
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Answer:
D) competition
Explanation:
They are going to be competing for their survival.
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- DNA codes fail to match accurately.
- The environment.
- Disclosure to chemical or radiation.
- <span> Mistake in the cellular machinery</span>
Answer:
- Glycine
- Ribulose 1,5-bisphosphate
- 3-phosphoglycerate
- Glyceraldehyde 3-phosphate.
- Glucose
- Sucrose
Explanation:
The glycine, among other amino acids, helps to improve chlorophyll production and promotes the process of photosynthesis.
<u>Calvin cycle</u>
During the carbon fixation phase, a CO² molecule combinate with a ribulose 1,5-bisphosphate to form 6-carbonated molecules, which will divide into two 3-phosphoglycerate molecules.
During the reduction phase, NADPH donates its electrons to reduce 3-phosphoglycerate molecules, and turn them into glyceraldehyde 3-phosphate.
During the regeneration phase, a glyceraldehyde 3-phosphate molecule leaves the cycle and goes to the cytosol to form glucose. This step can be done when three CO² enter the cycle and produce six glyceraldehyde 3-phosphate molecules. One of them leaves the cycle to form glucose, while the other five are recycled.
<u>Cytosol: </u>
Once in the cytosol, glyceraldehyde 3-phosphate molecules are used to form glucose and fructose. These two molecules are the monosaccharides that form the sucrose.
Once sucrose is formed, it is transported from the photosynthetic tissues to different parts of the plant by the phloem.
Answer:
After this treatment, the investigators should expect to get a mixture of the desired enzyme, plus fragments of the peptide used to desorb the enzyme in question.
This would be the result of using a peptide as a desorption solution when the desired protein is a protease,
Assuming that the protease retains its activity in the medium in question, and that the peptide can act as a substrate (which would make sense), as the peptide solution is added, it will interact with and bind to the antibody, but some molecules will also interact with the active site of the enzyme as it desorbs and passes through, culminating on the elution of the hydrolized part of the peptide along with the enzyme.
