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3 years ago

In terms of their location, what is the difference between subcutaneous fat and visceral fat

1 answer:

4 0

Subcutaneous fat is the fat that lies under the skin and isn’t necessarily harmful to your health and visceral fat is the harmful unseen fat surrounding the organs.

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a 2 meters tall person is located 5 meters from a camera lens (camera lens are convex lenses). the lens has a focal length of 35

ki77a [65]

Sorry that you got your answer late but the answer is 0.035m

3 0

3 years ago

Q1: What type of mechanical wave is produced by the action of this coiled spring?

erik [133]

Answer: A is Compression and B is Rarefaction.

Explanation:

i think it's right. hope it helps.

4 0

2 years ago

Read 2 more answers

I need both parts please (a) Given a material with an attenuation coefficient (a) of 0.6/cm, what is the intensity of a beam (wi

Masteriza [31]

Answer:

After it has traveled through 1 cm : $I(1 \ cm) = 0.5488 I_0$

After it has traveled through 2 cm : $I(2 \ cm) = 0.3012 I_0$

After it has traveled through 1 cm : $od( 1\ cm) = 0.2606$

After it has traveled through 2 cm : $od( 2\ cm) = 0.5211$

Explanation:

For this problem, we can use the Beer-Lambert law. For constant attenuation coefficient $\mu$ the formula is:

$I(x) = I_0 e^{-\mu x}$

where I is the intensity of the beam, $I_0$ is the incident intensity and x is the length of the material traveled.

For our problem, after travelling 1 cm:

$I(1 \ cm) = I_0 e^{- 0.6 \frac{1}{cm} \ 1 cm}$

$I(1 \ cm) = I_0 e^{- 0.6}$

$I(1 \ cm) = 0.5488 \ I_0$

After travelling 2 cm:

$I(2 \ cm) = I_0 e^{- 0.6 \frac{1}{cm} \ 2 cm}$

$I(2 \ cm) = I_0 e^{- 1.2}$

$I(2 \ cm) = 0.3012 \ I_0$

The optical density od is given by:

$od(x) = - log_{10} ( \frac{I(x)}{I_0} )$ .

So, after travelling 1 cm:

$od( 1\ cm) = - log_{10} ( \frac{0.5488 \ I_0}{I_0} )$

$od( 1\ cm) = - log_{10} ( 0.5488 )$

$od( 1\ cm) = - ( - 0.2606)$

$od( 1\ cm) = 0.2606$

After travelling 2 cm:

$od( 2\ cm) = - log_{10} ( \frac{0.3012 \ I_0}{I_0} )$

$od( 2\ cm) = - log_{10} ( 0.3012 )$

$od( 2\ cm) = - ( - 0.5211)$

$od( 2\ cm) = 0.5211$

3 0

3 years ago

In the diagram below, what is the property of the wave indicated by the letter A? a.Crest

Ugo [173]

Do you have a picture of the diagram that I could view?

4 0

3 years ago

Read 2 more answers

a Car with a mass of 2000 kg is moving around a circular curve at a uniform velocity of 25 m/s the curve has a radius of 80 m wh

Viefleur [7K]

Well, first of all, the car is not moving at a uniform velocity, because,
on a curved path, its direction is constantly changing. Its speed may
be constant, but its velocity isn't.

The centripetal force on a mass 'm' that keeps it on a circle with radius 'r' is

   F = (mass) · (speed)² / (radius).

For this particular car, the force is

(2,000 kg) · (25 m/s)² / (80 m)

   = (2,000 kg) · (625 m²/s²) / (80 m)

   = (2,000 · 625 / 80) (kg · m / s²)

   = 15,625 newtons .

5 0

3 years ago