<span>For given hyperbola:
center: (0,0)
a=7 (distance from center to vertices)
a^2=49
c=9 (distance from center to vertices)
c^2=81
c^2=a^2+b^2
b^2=c^2-a^2=81-49=32
Equation of given hyperbola:
..
2: vertices (0,+/-3) foci (0,+/-6)
hyperbola has a vertical transverse axis
Its standard form of equation: , (h,k)=(x,y) coordinates of center
For given hyperbola:
center: (0,0)
a=3 (distance from center to vertices)
a^2=9
c=6 (distance from center to vertices)
c^2=36 a^2+b^2
b^2=c^2-a^2=36-9=25
Equation of given hyperbola:
</span>
Answer:
the last picture
Step-by-step explanation:
the one where the line hits the -3 mark on the y-axis
The first one would be the right one!
you just take all the y one side and the numbers on one side
so 8y+4= 6+3y
now 8y-3y= 6-4
therefore 5y = 2
!!
Recall Euler's theorem: if 
, then
where 
is Euler's totient function.
We have 
- in fact, 
for any 
since 
and 
share no common divisors - as well as 
.
Now,
where the 
are positive integer coefficients from the binomial expansion. By Euler's theorem,
so that
45 hours.
80 - 70= 10, and 450/10 is 45.
to justify, you can do 70x45= 3,150, and 80x45= (3,600 - 3,150= 450)
