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3 years ago

Which quadratic equation is equivalent to (x^2-1)^2-11(x^2-1)+24=0

Mathematics

2 answers:

solniwko [45]3 years ago

8 0

Answer:

u² - 11u + 24 = 0 is equivalent to (x²-1)² - 11(x²-1) + 24 = 0

Step-by-step explanation:

(x²-1)² - 11(x²-1) + 24 = 0

Evaluate each equation by substituting the value of u to match the equation above.

1) u² - 11u + 24 = 0 where u = (x² - 1)

(x²-1)² - 11(x²-1) + 24 = 0

This equation matches (x²-1)² - 11(x²-1) + 24 = 0

2) (u²)² - 11(u²) + 24 where u = (x² - 1)

[(x²-1)²]² - 11(x²-1)² + 24

This equation does not match (x²-1)² - 11(x²-1) + 24 = 0

3) u² + 1 - 11u +24 = 0 where u = (x² - 1)

(x² - 1)² + 1 - 11(x²-1) + 24 = 0

This equation does not match (x²-1)² - 11(x²-1) + 24 = 0

4) (u² - 1)² - 11(u² - 1) + 24 where u = (x² - 1)

[(x²-1)²-1]² - 11(u² - 1)² + 24

This equation does not match (x²-1)² - 11(x²-1) + 24 = 0

Therefore, the first quadratic equation is equivalent to (x²-1)² - 11(x²-1) + 24 =0.

Y_Kistochka [10]3 years ago

3 0

Answer:

The correct answer is first option

u² - 11u + 24 = 0

When u = (x² - 1)

Step-by-step explanation:

It is given that,

(x² - 1)² - (x² - 1) + 24 = 0

To find the correct answer

Substitute u = x² - 1

The equation becomes,

u² - 11u + 24 = 0 Where u = (x² - 1)

Therefore the correct answer is first option

u² - 11u + 24 = 0

When u = (x² - 1)

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Hello!!

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$\mathbb{A~N~S~W~E~R~:}$

$= r$ · $2$

➡ $\Huge \sf \mathbb \color{}\underline{\colorbox{ANSWER~WITH~EXPLANATION ~!}{}}$

$\mathfrak{apply~the~fraction~rule: }$ $a$ $\frac{b}{c} =\frac{a~. ~b }{c}$

$\mathfrak{apply~rule: }$ $a$ · $1 = a$

$r$ · $1$ · $4 = r$ · $4$

$=\frac{r~.~4}{2}$

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$= r$ · $2$

So, your answer will be is :

$= r$ · $2$

$\color{}{Hope\:it\:helps. ..}$

#LearnWithBrainly

$\mathbb{A~N~S~W~E~R~:}$

$\mathfrak{Jace}$

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