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antoniya [11.8K]
3 years ago
13

Which quadratic equation is equivalent to (x^2-1)^2-11(x^2-1)+24=0

Mathematics
2 answers:
solniwko [45]3 years ago
8 0

Answer:

u² - 11u + 24 = 0 is equivalent to (x²-1)² - 11(x²-1) + 24 = 0

Step-by-step explanation:

(x²-1)² - 11(x²-1) + 24 = 0

<em>Evaluate each equation by substituting the value of u to match the equation above.</em>

1) u² - 11u + 24 = 0 where u = (x² - 1)

(x²-1)² - 11(x²-1) + 24 = 0

<em>This equation matches (x²-1)² - 11(x²-1) + 24 = 0</em>

2) (u²)² - 11(u²) + 24 where u = (x² - 1)

[(x²-1)²]² - 11(x²-1)² + 24

<em>This equation does not match (x²-1)² - 11(x²-1) + 24 = 0</em>

3) u² + 1 - 11u +24 = 0 where u = (x² - 1)

(x² - 1)² + 1 - 11(x²-1) + 24 = 0

<em>This equation does not match (x²-1)² - 11(x²-1) + 24 = 0</em>

4) (u² - 1)² - 11(u² - 1) + 24 where u = (x² - 1)

[(x²-1)²-1]² - 11(u² - 1)² + 24

<em>This equation does not match (x²-1)² - 11(x²-1) + 24 = 0</em>

Therefore, the first quadratic equation is equivalent to (x²-1)² - 11(x²-1) + 24 =0.

!!

Y_Kistochka [10]3 years ago
3 0

Answer:

The correct answer is first option

u² - 11u + 24 = 0

When u = (x² - 1)

Step-by-step explanation:

It is given that,

(x² - 1)² - (x² - 1) + 24 = 0

<u>To find the correct answer</u>

Substitute u = x² - 1

The equation becomes,

u² - 11u + 24 = 0 Where u = (x² - 1)

Therefore the correct answer is first option

u² - 11u + 24 = 0

When u = (x² - 1)

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