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neonofarm [45]
3 years ago
10

A 2.0-kg mass (mA) and a 4.0-kg mass (mB) are connected to a lightweight cord that passes over a frictionless pulley. The pulley

only changes the direction of the force exerted by the rope. The hanging masses are free to move. Choose coordinate systems for the two masses with the positive direction up for mA and down for mB.
(a) Create a pictorial model.
(b) Create a physical model with motion and free-body diagrams. (Do parts a and b on paper. Your instructor may ask you to turn in this work.) This answer has not been graded yet.
(c) What is the acceleration of the smaller mass.
Physics
1 answer:
Flura [38]3 years ago
7 0

Answer:

i dont have such a type of keyboard so, i can't solve it sorry

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Arte-miy333 [17]

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<span>3. The attempt at a solution So basically what I did was divided into components. x: (3)(2000) = (3000)*v_x y: (v_vw)*(10000) = (3000)*v_y v_x, v_y is the velocity (after collision) in the x and y direction, respectively, of both cars stuck together (since it is an inelastic collision). v_vw is the initial velocity of the Volkswagen. Now what I did was that the angle is 35 degrees north of east. So basically made a triangle and figured that tan(35) = (v_y)/(v_x). This means (v_x)*(tan35) = v_y. Then, I simplified the component equations to get: x: 2 = v_x y: v_vw = 3*v_y Then plugging in for v_y, I got: v_vw = 3(2)(tan35) = 4.2 m/s as the velocity of the volkswagen. However, the answer key says 8.6 m/s. Could someone please help me out? Thanks Phys.org - latest science and technology news stories on Phys.org • Game over? Computer beats human champ in ancient Chinese game • Simplifying solar cells with a new mix of materials • Imaged 'jets' reveal cerium's post-shock inner strength Oct 24, 2012 #2 ehild Homework Helper Gold Member What directions you call x and y? Reference https://www.physicsforums.com/threads/2d-momentum-problem.646613/</span>
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