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erma4kov [3.2K]

2 years ago

14

an object is held 33.5 cm from a convex mirror. it creates a virtual image of magnification 0.253. what is the focal length of t

he mirror?

1 answer:

MaRussiya [10]2 years ago

7 0

Answer:

Magnification= -image distance/object distance

.253=image distance/33.5

image distance= 8.48 cm

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Absolute potential difference ,due of point charge of 1C at a distance of 1 m is given by

astra-53 [7]

Answer:

$\implies U = \dfrac{kq}{r}$

$\implies U = \dfrac{9 \times {10}^{9} \times 1}{1}$

$\implies U = 9 \times {10}^{9} \: J$

3 0

3 years ago

Who founded Electronic Arts?

GREYUIT [131]

Answer:

trips Hawkins founded electronic arts

5 0

3 years ago

The Whirlpool galaxy is about 30 million light-years away. If you were in a spaceship that could travel at half of the speed of

Nataly_w [17]

Answer:

51.96 years

2) 30 million of years

Explanation:

First we must know the travel time of the ship seen from the earth. The spaceship travels at half the speed of light, this means that the amount of time the spacecraft must spend to travel the same distance is double compared to the light, that is 60 years.

Now due to the speed of the ship, we must take into account relativistic effects, such as time dilation, this is given by:

$t'=\frac{t}{\sqrt{1-\frac{v^2}{c^2}}}$

Where t is the time measured in the ship, t' is the time measured in the earth, inertially moving with velocity v.

Rewriting for t:

$t=t'\sqrt{1-\frac{v^2}{c^2}}\\t=60\sqrt{1-\frac{(0.5c)^2}{c^2}}\\t=60\sqrt{1-0.5^2}\\t=51.96 years$

This is the amount of time it would take you reach the Whirlpool galaxy in the spaceship.

2) a light year is a measure of distance, which indicates the kilometers that light travels in a year. Thus, the light emitted by Whirlpool galaxy takes 30 million of years reaches our planet.

6 0

3 years ago

One person is in a pool and is diving to a depth of 2.3m, and another person is diving to a depth of 3m. What pressure does each

Vlad [161]

Explanation:

The static pressure is P = ρgh, where ρ is the density of the fluid and h is the depth.

For the first person:

P = (1000 kg/m³) (9.8 m/s²) (2.3 m)

P = 22,500 Pa

For the second person:

P = (1000 kg/m³) (9.8 m/s²) (3 m)

P = 29,400 Pa

6 0

3 years ago

Two runners start simultaneously from the same point on a circular 200-m track and run in the same direction. One runs at a cons

sladkih [1.3K]

Answer

given,

length of the track = 200 m

speed of runner 1 = 6.20 m/s

speed of the runner 2 = 5.5 m/s

distance covered by the fastest runner, d = 6.2 t

distance covered by the slow runner,d = 5.50 t + 200

time taken to overtake for the first time

6.2 t = 5.50 t + 200

0.7 t = 200

t = 285.7 s

distance covered from the starting point

d = 6.2 t

d = 6.2 x 285.7

d = 1771.43 m

for next overtaking time taken will be double

t' = 258.7 x 2 = 571.4 s

distance travel by the runner from the starting point

d' = 6.2 t'

d' = 6.2 x 571.4

d' = 3542.68 m

5 0

4 years ago