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erma4kov [3.2K]
2 years ago
14

an object is held 33.5 cm from a convex mirror. it creates a virtual image of magnification 0.253. what is the focal length of t

he mirror?
Physics
1 answer:
MaRussiya [10]2 years ago
7 0

Answer:

Magnification= -image distance/object distance

.253=image distance/33.5

image distance= 8.48 cm

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Potential difference (V) = 2.0 V

Current flowing (I) = 4.0 A

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Area of cross section of wire (A) = 1.0 mm² = 1 × 10⁻⁶ m² [1 mm² = 10⁻⁶ m²]

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R=\frac{V}{A}=\frac{2.0}{4.0}=0.5\ \Omega

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Now, conductivity of a material is the reciprocal of its resistivity. Therefore, the conductivity of Nichrome is given as:

\sigma=\frac{1}{\rho}=\frac{1}{0.5\times 10^{-6}}=2\times 10^6\ S/m

Conductivity is measured in Siemens per meter (S/m)

Therefore, the conductivity of Nichrome is 2\times 10^6\ S/m.

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