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erma4kov [3.2K]
2 years ago
14

an object is held 33.5 cm from a convex mirror. it creates a virtual image of magnification 0.253. what is the focal length of t

he mirror?
Physics
1 answer:
MaRussiya [10]2 years ago
7 0

Answer:

Magnification= -image distance/object distance

.253=image distance/33.5

image distance= 8.48 cm

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A string with linear density 0.500 g/m.

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We are given following data for string with linear density held under tension :

μ = 0.5 \frac{g}{m}

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T = 20 N

If string is L = 3m long, total energy as a function of v_{y, max} is given by:

E = 1/2 x μ x L x ω² x A²

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So, The total energy as a function of  v^{2} _{y, max} = 7.5 x 10⁻⁴ v^{2} _{y, max}

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2 years ago
Ignoring air resistance, if a 20 kg ball and a 400 kg crate were both dropped from the
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4 years ago
Which of the following properties are not likely to be the target of community redevelopment programs?
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B. New homes

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