Answer:
y = -0.42 m
1.16*10^-4 T(-k)
-1.73*10^4 N/C (j)
Explanation:
(a) Above the pair of wires, The field out of the page of the 50 A current will be stronger than the (—k) field of the 30 A current (k).
Between the wires, both produce fields into the page.
below the wires, y = - | y |
B = u_o*I/2πr (-k) + u_o*I/2πr (k)
0 = u_o/2πr[50/ | y |+0.28 (-k) + 30/| y | (k) ]
50 | y | = 30(| y | + 0.28)
| y | = -y
-50 y = 30*(0.28 - y)
y = -0.42 m
b) B = u_o*I/2πr (-k) + u_o*I/2πr (k)
B = 4π*10^-7/2π[ 50/0.28 -1 (-k) +30/1(-k) ]
= 1.16*10^-4 T(-k)
F = qv*B
F = (-2*10^-6)*(150*10^6(i) )(1.16*10^-4(-k))
F = 3.47*10^-2 N(-j)
c) F_e = qE
E = F_e/q
E = 3.47*10^-2/-2*10-6
= -1.73*10^4 N/C (j)
The tension force being supplied by the rope is 245 N.
<h3>What is tension force?</h3>
- Tension force is the force exerted on a rope or cord due to the weight of an object suspended from it.
The tension force on the given rope due to the weight of the lamp hanging from the rope is calculated by applying Newton's second law of motion as shown below;
T = mg
where;
- m is the mass = 25 kg
- g is acceleration due to gravity = 9.8 m/s²
T = 25 x 9.8
T = 245 N
Thus, the tension force being supplied by the rope is 245 N.
Learn more about tension force here: brainly.com/question/2008782
Answer:
B
Explanation:
OOf we are doing this stuff atm
So if its faster at the front and slow at the back you can tell that its not slowing down because less of a force is there however at the front there is more of a force. Friction is low which means that its not makimg much contact so no sudden change of forces thats also why its B
Answer:
13.8 N
Explanation:
Pressure on the one end of the hydraulic system = Pressure on the other end
Pressure = Force / Area where Force is in Newton, area is in m²
so Force of one end (F1) / area of that end = force of the other end (F2) / area of that end
3112 / ( 707 /10000) in m² = F2 / ( 3.14 / 10000) in m²
cross multiply
44016.97 × 0.000314 = 13.82 N
Given:
500 containers ; 5 of these are defective.
A = event that 1st is defective = 5/500
B = event that 2nd is defective = 4/499
C = event that 3rd is defective = 3/498
a) 4/499
b) 5/500 * 4/499 = 20/249,500 = 1/12,475
c) 495/500 * 494/500 = 244,530 / 250,000 = 24,453/25,000
d) 5/500 * 4/499 * 3/498 = 60/124,251,000 = 1/2,070,850
