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Aliun [14]
3 years ago
12

What do these substances have in common? apple juice, helium gas, salt water and copper wire

Chemistry
2 answers:
JulsSmile [24]3 years ago
7 0

They are all compounds! Good Luck Mate!

Llana [10]3 years ago
6 0

Answer;

They are compounds

Explanation;

A compound is a substance formed when two or more elements are chemically joined. Water, salt, and sugar are examples of compounds.

When the elements are joined, the atoms lose their individual properties and have different properties from the elements they are composed of.

Elements are substances that cannot be separated into simpler substances.

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The illumination of an object by a light source is directly proportional to the strength of the source and inversely proportiona
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<span>Exactly 4(4 - 2*2^(1/3) + 2^(2/3)) feet, or approximately 12.27023581 feet. Let's first create an equation to calculate the relative intensity of the light based upon the distance D from the brighter light source. The distance from the dimmer light source will of course be (20-D). So the equation will be: B = 4/D^2 + 1/(20-D)^2 The minimum and maximum can only occur at those points where the slope of the equation is 0. And you can determine the slope by using the first derivative. So let's calculate the first derivative. B = 4/D^2 + 1/(20-D)^2 B' = d/dD [ 4/D^2 + 1/(20-D)^2 ] B' = 4 * d/dD [ 1/D^2 ] + d/dD [ 1/(20-D)^2 ] B' = 4(-2)D^(-3) + (-2)(20 - D)^(-3) * d/dD [ 20-D ] B' = -8/D^3 - 2( d/dD [ 20 ] - d/dD [ D ] )/(20 - D)^3 B' = -8/D^3 - 2(0 - 1)/(20 - D)^3 B' = 2/(20 - D)^3 - 8/D^3 Now let's find a zero. B' = 2/(20 - D)^3 - 8/D^3 0 = 2/(20 - D)^3 - 8/D^3 0 = 2D^3/(D^3(20 - D)^3) - 8(20 - D)^3/(D^3(20 - D)^3) 0 = (2D^3 - 8(20 - D)^3)/(D^3(20 - D)^3) 0 = 2D^3 - 8(20 - D)^3 8(20 - D)^3 = 2D^3 4(20 - D)^3 = D^3 4(8000 - 1200D + 60D^2 - D^3) = D^3 32000 - 4800D + 240D^2 - 4D^3 = D^3 32000 - 4800D + 240D^2 - 5D^3 = 0 6400 - 960D + 48D^2 - D^3 = 0 -6400 + 960D - 48D^2 + D^3 = 0 D^3 - 48D^2 + 960D - 6400 = 0 We now have a simple cubic equation that we can use the cubic formulas to solve. Q = (3*960 - (-48)^2)/9 = 64 R = (9*(-48)*960 - 27*(-6400) - 2*(-48)^3)/54 = -384 D = Q^3 + R^2 = 64^3 + (-384)^2 = 409600 Since the value D is positive, there are 2 imaginary and 1 real root. We're only interested in the real root. S = cbrt(-384 + sqrt(409600)) S = cbrt(-384 + 640) S = cbrt(256) S = 4cbrt(4) T = cbrt(-384 - sqrt(409600)) T = cbrt(-384 - 640) T = cbrt(-1024) T = -8cbrt(2) The root will be 4cbrt(4) - 8cbrt(2) + 48/3 So simplify 4cbrt(4) - 8cbrt(2) + 48/3 =4cbrt(4) - 8cbrt(2) + 16 =4(cbrt(4) - 2cbrt(2) + 4) = 4(4 - 2*2^(1/3) + 2^(2/3)) Which is approximately 12.27023581 This result surprises me. I would expect the minimum to happen where the intensity of both light sources match which would be at a distance of 2/3 * 20 = 13.3333 from the brighter light source. Let's verify the calculated value. Using the brightness equation at the top we have: B = 4/D^2 + 1/(20-D)^2 Using the calculated value of 12.27023581, we get B = 4/D^2 + 1/(20-D)^2 B = 4/12.27023581^2 + 1/(20-12.27023581)^2 B = 4/12.27023581^2 + 1/7.72976419^2 B = 4/150.5586868 + 1/59.74925443 B = 0.026567713 + 0.016736611 B = 0.043304324 And the intuition value of 13.33333333 B = 4/D^2 + 1/(20-D)^2 B = 4/13.33333333^2 + 1/(20-13.33333333)^2 B = 4/13.33333333^2 + 1/6.666666667^2 B = 4/177.7777778 + 1/44.44444444 B = 0.0225 +0.0225 B = 0.045 And the calculated value is dimmer. So intuition wasn't correct. So the object should be placed 4(4 - 2*2^(1/3) + 2^(2/3)) feet from the stronger light source, or approximately 12.27023581 feet.</span>
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3 years ago
Balance this equation-<br> Na3PO4 + KOH -&gt; NaOH + K3PO4
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How does heat affect water and its state of matter
Kryger [21]

Answer:If a liquid is heated the particles are given more energy and move faster and faster expanding the liquid. The most energetic particles at the surface escape from the surface of the liquid as a vapour as it gets warmer. Liquids evaporate faster as they heat up and more particles have enough energy to break away.

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2 years ago
Balance the equation by inserting coefficients as needed. equation: ZnS + HBr -&gt; ZnBr_{2} + H_{2}S ZnS + HBr ⟶ ZnBr 2 + H 2 S
yawa3891 [41]

Answer : The balanced chemical reaction will be,

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Explanation :

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

If the amount of atoms of each type on the left and right sides of a reaction differs then to balance the equation by adding coefficient in the front of the elements or molecule or compound in the chemical equation.

The coefficient tell us about that how many molecules or atoms present in the chemical equation.

The given chemical reaction is,

ZnS+HBr\rightarrow ZnBr_2+H_2S

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In order to balance the chemical equation, the coefficient '2' put before the HBr and we get the balanced chemical equation.

The balanced chemical reaction will be,

ZnS+2HBr\rightarrow ZnBr_2+H_2S

8 0
3 years ago
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