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guajiro [1.7K]
3 years ago
5

Can u help me and ty :))

Chemistry
2 answers:
Roman55 [17]3 years ago
3 0

Answer:

3.166

Explanation:

energy=30J

input =95J

efficiency=?

efficiency= input/energy

= 95/30

=3.166

katen-ka-za [31]3 years ago
3 0

Answer:

3.166

Explanation:

= 95/30

=3.166

 

  Hope this helped!!

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4 years ago
How many grams of potassium fluoride can form if 4.00 grams of potassium are reacted with 3.00 grams of fluorine gas according t
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Answer:

We can for 5.93 grams potassium fluoride

Explanation:

Step 1: Data given

Mass of potassium = 4.00 grams

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Molar mass fluorine gas =38.00 g/mol

Step 2: The balanced equation

2K (s) + F2 (g) → 2KF (s)

Step 3: Calculate moles potassium

Moles potassium = 4.00 grams / 39.10 g/mol

Moles potassium = 0.102 moles

Step 4: Calculate moles F2

Moles F2 = 3.00 grams / 38.00 g/mol

Moles F2 = 0.0789 moles

Step 5: Calculate limiting reactant

Potassium is the limiting reactant. There will react 0.102 moles

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There will remain 0.0789 - 0.051 = 0.0279 moles

Step 6: Calculate moles potassium fluoride

For 2 moles potassium we need 1 mol fluorine to produce 2 moles potassium fluoride

For 0.102 moles K we need 0.102 moles KF

Step 7: Calculate mass KF

Mass KF = moles KF * molar mass KF

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3 0
4 years ago
An ionic bond is formed between a cation A1 and an anion B2. How would the energy of the ionic bond [see Equation (9.2)] be affe
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Answer:

Before we start answering, the appropiate equation for the energy of an ionic bond should be written:

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Explanation:

Examining the equation above, we have the following scenarios:

a) Doubling the radius of A1 would mean a decrease on the energy of the ionic bond.

b) Tripling the charge of A1 would also triple the energy of the ionic bond

c)Doubling the charges on A1 and B2 would quadruple the energy of the ionic bond.

d)Decreasing the radii of A1 and B2 to half their original values would double the energy of the energy bond.

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3 years ago
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amm1812

Answer:

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